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Full Discussion: The meaning of %s in printf
Top Forums UNIX for Dummies Questions & Answers The meaning of %s in printf Post 302420063 by quirkasaurus on Monday 10th of May 2010 12:47:19 PM
Old 05-10-2010
Quote:
Originally Posted by cosmologist
I have this command like that has %s in it, I know %s calls a column, but I am not sure I understand which column (I mean for my case I can check the input file, but I want to know how is this %s used, how comes tha same symbo; gives different columns in one command line:

Code:
{printf "grep %s junk.all.dat | awk '$4<=%s{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat\n"}

Each %s give a different column in the output:

Code:
grep 3a junk.all.dat | awk '$4<=157.951{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat
grep 7a junk.all.dat | awk '$4<=118.793{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat
grep 9a junk.all.dat | awk '$4<=133.435{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat

Any idea how this %s works?
OKay, so I grunched this thread other than the first few posts.
In there no one mentioned how this line here:

Code:
{printf "grep %s junk.all.dat | awk '$4<=%s{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat\n"}

Is missing some arguments. At any rate... The %s are formatting strings that printf interprets to mean "print the associated argument as a string".

In this command, however, there are no arguments to printf.
On my system, this doesn't even work.

But making some modifications and attempting to stick with the original intent, I got this to work:

Code:
2158 -> cat a.awk
{
printf( "grep %s junk.all.dat | awk '$4 <= %s{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat\n",
  $1, $2 );
}

2159 -> date | awk -f a.awk
grep Mon junk.all.dat | awk '$4 <= May{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat

I'm probably late to the game -- but HTH.
 

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LEARN ABOUT PHP

db2_field_precision

DB2_FIELD_PRECISION(3)							 1						    DB2_FIELD_PRECISION(3)

db2_field_precision - Returns the precision of the indicated column in a result set

SYNOPSIS

       int db2_field_precision (resource  $stmt, mixed	$column)

DESCRIPTION

	Returns the precision of the indicated column in a result set.

PARAMETERS

	      o $stmt
		- Specifies a statement resource containing a result set.

	      o $column
		-  Specifies  the  column in the result set. This can either be an integer representing the 0-indexed position of the column, or a
		string containing the name of the column.

RETURN VALUES

	Returns an integer containing the precision of the specified  column.  If  the	specified  column  does  not  exist  in  the  result  set,
       db2_field_precision(3) returns FALSE.

SEE ALSO

       db2_field_display_size(3), db2_field_name(3), db2_field_num(3), db2_field_scale(3), db2_field_type(3), db2_field_width(3).

PHP Documentation Group 												    DB2_FIELD_PRECISION(3)
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