I was not talking about scripts and functions in general, but this special case. And if this function is called properly, then there is only one argument.
Quote:
Originally Posted by alister
That is absolutely incorrect. If there are multiple arguments passed to a script or function, the double-quoted values "$*" and "$@" will ALWAYS differ.
Thats right, but this function does only have one argument. If more than one argument is passed, it is just a plain syntax error, which should be handled properly (which bash should do too - ignoring a syntax error doesn't seem to be a very good implementation).
When you call ksh's cd function with extra arguments (in this case a third one), it says
Hi guys,
I have no idea on unix but suddenly, my cobol programs calls a unix script that i know nothing about.
can you guys interpret these lines for me?
i know its a print command but I want to actually know how many copies it prints.
qprt -da -P $1 -t '6' -i '6' -l '70' $2
qprt -da... (1 Reply)
Could you interpret the following sed and awk command for me?
command:
cat tempfile2 |sed "s/\(BUILD-3-.*-\.-\)\(.*\..*\..*\)/\2/" | awk '{printf "%-8.8s %-23.23s %-30.30s %-50.50s\n", $1,$2,$3,substr($0,index($0,$4))}' > outfile2 2>/dev/null
input:(data in tempfile2)... (1 Reply)
Hi,
So I am new to Unix, and I need to check the performance of some apps I am running. But I don't know how to interpret the output from TOP.
Could somebody please explain the difference between the different values. And also explain how I can have a process which has a %CPU > 100?
... (7 Replies)
hi
I have a text file abc.txt as below
a = 0
b = 1
c = 3
i want to interpret this file i.e. if number corresponding to 'a' is 0 i want to run a script script.bash .
How do do that? (4 Replies)
I have collected data of Number of L2 cache misses using PAPI. I had run an MPI application with 4 threads (mpirun -np 4) and each thread reads the cache misses in L2. Each thread outputs data for every timestamp. eg:
Timestamp data
xxx530 thread# 0 2136
xxx531 thread# 0 ... (0 Replies)
I know $0 is the entire file's contents (at least I think that is what it is!), but what exactly is: $0!~
This was a snippet from a larger line
awk '$0!~/^$/ {print $0}'
This deletes blank lines, but I want to know specifically the $0!~ part... I am guessing /^$/ is regex for blank line...... (5 Replies)
Can anyone tell me how to interpret this:
listpage="ls |more" (the spaces are there in the example)
$listpage
It's from my bash book and I'm not sure what it means (3 Replies)
hi All,
i have never used sed in Unix environment, but i have one script which is using this following command:
cat audit_session_rpt_MSP_20140331.lst|sed -n '/Apr 14/!p'| sed -n '/Page/!p'| sed -n '/UserName/!p' |\
egrep -v '^-|^=|^\*'|sed '/^$/d'|sed -e '1,7d'... (1 Reply)
I booted into single user mode with
/usr/sbin/reboot -- -s
but after doing a control -d
my
who -r
shows
run-level 3 Nov 17 14:07 3 0 S
I was expecting it to show run-level S
why is this still in run level 3?
thanks (1 Reply)