Here is a slightly modified example based on the above.
First we reformat the date to YYYYMMDD format.
Then for each date we compute the number of seconds since 1970-01-01 00:00:00 UTC (parameter %s of the date function)
Finally the result is divided by 86400 (number of seconds in a day).
does anybody know how to find out the number of
days elapsed between 2 dates
e.g.
days elapsed between 020212 and 020110 (YYMMDD format)
Thanking you in advance.
Ravi. (1 Reply)
Hi All
How to get the difference between two dates in no of days ??? My date format is like this YYYY/MM/DD. I have to get the no of days between two dates in the given format.
I tried to search the forum but nothing came up similar to my requitement. Your help will be appreciated.
... (1 Reply)
Hi All,
Can unix cshell list out the number of days between 070201 and 070205 (format is yymmdd) and list out all the dates in between in similiar format.
set startdate = `date '+%y%m%d'` #eg 070201
set enddate = `date '+%y%m%d'` #eg 070205
i would expect the number of days to be 5... (2 Replies)
Hi
I'm looking for a .ksh script/function that will calculate ONLY the number of days between two distinct dates. Further convert the number of days to weeks and display. I need this to be part of another larger script that checks the password expiry on several servers and notifies the... (1 Reply)
Hello,
I would like to find out the number of days between two dates of the format yyyy-mm-dd.
Any help on this is highly appreciated.
Thanks. (6 Replies)
I have two times in the format of YYMMDD. Does anyone know an easy way in ksh for me to display how many days are between the two dates?
Example1:
X=101202
Y=101205
There are 3 days between X & Y
Example2:
X=101202
Y=111202
There are 365 days between X & Y
Example3:
X=101205... (3 Replies)
I wrote the day calculator also in bash. I would like to now, that is it good so?
#!/bin/bash
datum1=`date -d "1991/1/1" "+%s"`
datum2=`date "+%s"`
diff=$(($datum2-$datum1))
days=$(($diff/(60*60*24)))
echo $days
Thanks in advance for your help! (3 Replies)
Hi Am using Unix Ksh
I have a two date input as
DATE1=02/12/2012
DATE2=30/12/2012
I Need the output as only sunday date
02/12/2012
09/12/2012
16/12/2012
23/12/2012
30/12/2012
can anyone pls help me..
thanks in advance... (2 Replies)
Gents.
Please can u help.
I would like to calculate the days between two dates.
Example file1 ( previous date)
file1 - Input file
9/29/2010 10195
9/29/2010 1057
2/2/2016 10
2/2/2016 10169
2/2/2016 1057
2/3/2016 10005
2/3/2016 10014
In file2 I add the actual date using this code.... (9 Replies)
Discussion started by: jiam912
9 Replies
LEARN ABOUT PHP
px_timestamp2string
PX_TIMESTAMP2STRING(3)PX_TIMESTAMP2STRING(3)px_timestamp2string - Converts the timestamp into a string.SYNOPSIS
string px_timestamp2string (resource $pxdoc, float $value, string $format)
DESCRIPTION
Turns a timestamp as it stored in the paradox file into human readable format. Paradox timestamps are the number of miliseconds since
0001-01-02. This function is just for convenience. It can be easily replaced by some math and the calendar functions as demonstrated in the
following example.
PARAMETERS
o $pxdoc
- Resource identifier of the paradox database.
o $value
- Value as stored in paradox database field of type PX_FIELD_TIME, or PX_FIELD_TIMESTAMP.
o $format
- String format similar to the format used by date(3). The placeholders support by this function is a subset of those supported by
date(3) (Y, y, m, n, d, j, H, h, G, g, i, s, A, a, L).
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
Turn a paradox timestamp into a human readable form
<?php
$px = px_new();
/* make up a date as it could be stored in */
/* a date field of a paradox db. */
/* 700000 days since 1.1.0000. */
$days = 700000;
/* Use the calendar functions to print a */
/* human readable format of the date */
echo jdtogregorian($days+1721425)."
";
/* Turn it into a timestamp as it stored in a paradox database */
/* Timestamps are stored in miliseconds since 0001-01-02 */
$stamp = $days * 86400.0 * 1000.0;
/* Add one hour */
$stamp += 3600000.0;
/* The following will output '7/15/1917 01:00:00'. */
echo px_timestamp2string($px, $stamp, "n/d/Y H:i:s")."
";
px_delete($px);
?>
The above example will output:
7/15/1917
7/15/1917 01:00:00
The Julian day count as passed to jdtogregorian(3) has a different base of 1.1.4714 b.c. and must therefore be calculated by adding
1721425 to the day count used in the paradox file. Turning the day count into a timestamp is easily done by multiplying with 86400000.0 to
obtain miliseconds.
SEE ALSO px_date2string(3), jdtogregorian(3).
PHP Documentation Group PX_TIMESTAMP2STRING(3)