Sponsored Content
Top Forums Shell Programming and Scripting How to remove all words starting from a matching word in a line Post 302416062 by spider007 on Saturday 24th of April 2010 04:15:11 PM
Old 04-24-2010
You can use this to get everything before the pattern yyy.
Here I used yyy pattern as field seperator.

Code:
 
cat file|awk -F 'yyy' '{print $1}'

Thanks
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

remove first few words from a line

Hi All, Sample: 4051 Oct 4 10:03:36 AM 2008: TEST: end of testcase Checking Interface after reload, result fail I need to remove first 10 words of the above line and output should be like Checking Interface after reload, result fail Please help me in this regard. Thanks, (4 Replies)
Discussion started by: shellscripter
4 Replies

2. Shell Programming and Scripting

How to remove all words from a matching word in a line?

Hi Guys, :p I have a file like this: 2010-04-25 00:00:30,095 INFO - ]- start process U100M4 2010-04-25 00:00:30,096 DEBUG - ] -- call EJB 2010-04-25 00:00:30,709 INFO - - end processU100M4 2010-04-25 00:00:30,710 DEBUG - got message=Sorry I want to out put format. 2010-04-25... (5 Replies)
Discussion started by: ooilinlove
5 Replies

3. Shell Programming and Scripting

Using awk to print line starting with particular word

Hi Geeks, Consider this line: driver=c:\folder1\folder2 The above line is contained in a variable say 'var' . I want to copy everything after 'driver=' in to another variable say var2. Please tell me how can this be done. (8 Replies)
Discussion started by: ajincoep
8 Replies

4. UNIX for Advanced & Expert Users

cut words based on the word count of a line

I would like to cut words based on the word count of a line. This over here inspired me with some ideas but I wasn't able to get what I needed. https://www.unix.com/shell-programming-scripting/105841-count-words-each-line-file-using-xargs.html If the line has 6 words I would like to use this.... (8 Replies)
Discussion started by: cokedude
8 Replies

5. Shell Programming and Scripting

Remove last few words from Line

Hi I would like to remove last few words from File Could anybody Help on it. ps -ef | grep mgr.prm | awk '{print $10}' /opt/app/dummyd/xyz/dirprm/mgr.prm /opt/app/dummy/xyz/dirprm/mgr.prm /opt/app/dummy/xyz/dirprm/mgr.prm I want output like /opt/app/dummyd/xyz... (4 Replies)
Discussion started by: tapia
4 Replies

6. Shell Programming and Scripting

Remove duplicate line starting with a pattern

HI, I have the below input file /* ----------------- cmdsDlyStartFWJ -----------------*/ UNIX_JOB CMDS065J RUN ANY CMDNAME sleep 5 AGENT CMDSHP USER proddata RUN MON,TUE,WED,THU,FRI DELAYSUB 02:00 /* "Triggers daily file watcher jobs" */ ENVAR... (5 Replies)
Discussion started by: varun22486
5 Replies

7. UNIX for Advanced & Expert Users

Sort words based on word count on each line

Hi Folks :) I have a .txt file with thousands of words. I'm trying to sort the lines in order based on number of words per line. Example from: word word word word word word word word word word word word word word word word to desired output: word (2 Replies)
Discussion started by: martinsmith
2 Replies

8. Shell Programming and Scripting

Get first word only starting of a line

Hi, I am trying to get longest line in a .gz file without extract the file. I am using the below command to get the longest line. zcat /a/b/c/file.gz |awk '{print length, $0}'|sort -nr|head -1 247 AAAAAAAAAAAAAAAAAAAAAAAAA BBBBBBBBBBBBBBBBBBBAAAAAA CCCCCCCCCCC DDDDDDDDDDDD EEEEEEEEEEEEEE... (4 Replies)
Discussion started by: k_manimuthu
4 Replies

9. UNIX for Beginners Questions & Answers

Grep file starting from pattern matching line

I have a file with a list of references towards the end and want to apply a grep for some string. text .... @unnumbered References @sp 1 @paragraphindent 0 2017. @strong{Chalenski, D.A.}; Wang, K.; Tatanova, Maria; Lopez, Jorge L.; Hatchell, P.; Dutta, P.; @strong{Small airgun... (1 Reply)
Discussion started by: kristinu
1 Replies

10. Shell Programming and Scripting

Remove new line starting with a numeric value and append it to the previous line

Hi, i have a file with multiple entries. After some tests with sed i managed to get the file output as follows: lsn=X-LINK-IN0,apc=661:0,state=avail,avail/links=1/1, 00,2110597,2094790,0,81,529,75649011,56435363, lsn=TM1ITP1-AM1ITP1-LS,apc=500:0,state=avail,avail/links=1/1,... (5 Replies)
Discussion started by: nms
5 Replies
FC-PATTERN(1)															     FC-PATTERN(1)

NAME
fc-pattern - parse and show pattern SYNOPSIS
fc-pattern [ -cdVh ] [ --config ] [ --default ] [ [ -f format ] [ --format format ] ] [ --version ] [ --help ] [ pattern [ element... ] ] DESCRIPTION
fc-pattern parses pattern (empty pattern by default) and shows the parsed result. If --config is given, config substitution is performed on the pattern before being displayed. If --default is given, default substitution is performed on the pattern before being displayed. If any elements are specified, only those are printed. OPTIONS
This program follows the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is included below. -c Perform config substitution on pattern. -d Perform default substitution on pattern. -f Format output according to the format specifier format. -V Show version of the program and exit. -h Show summary of options. pattern Parses and displays pattern (uses empty pattern by default). element If set, the element property is displayed for parsed pattern. SEE ALSO
FcNameParse(3) FcConfigSubstitute(3) FcDefaultSubstitute(3) FcPatternPrint(3) FcPatternFormat(3) fc-cat(1) fc-cache(1) fc-list(1) fc- match(1) fc-query(1) fc-scan(1) The fontconfig user's guide, in HTML format: /usr/share/doc/fontconfig/fontconfig-user.html. AUTHOR
This manual page was updated by Behdad Esfahbod <behdad@behdad.org>. Apr 20, 2010 FC-PATTERN(1)
All times are GMT -4. The time now is 04:45 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy