04-24-2010
Get number of days between given dates
Hi
I need one single command to get number of days between
two given dates.datecalc is not working.
ex.
fromdate:01.04.2010
todate :24.04.2010
i should get the out put as 23
Thanks in advance
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does anybody know how to find out the number of
days elapsed between 2 dates
e.g.
days elapsed between 020212 and 020110 (YYMMDD format)
Thanking you in advance.
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Hi All
How to get the difference between two dates in no of days ??? My date format is like this YYYY/MM/DD. I have to get the no of days between two dates in the given format.
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Hi All,
Can unix cshell list out the number of days between 070201 and 070205 (format is yymmdd) and list out all the dates in between in similiar format.
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I'm looking for a .ksh script/function that will calculate ONLY the number of days between two distinct dates. Further convert the number of days to weeks and display. I need this to be part of another larger script that checks the password expiry on several servers and notifies the... (1 Reply)
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Hello,
I would like to find out the number of days between two dates of the format yyyy-mm-dd.
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I have two times in the format of YYMMDD. Does anyone know an easy way in ksh for me to display how many days are between the two dates?
Example1:
X=101202
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There are 3 days between X & Y
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X=101202
Y=111202
There are 365 days between X & Y
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Is this code good for this purpose?
<?php
$date1 = mktime(0,0,0,01,01,1991);
$date2 = mktime(0,0,0,03,22,2012);
$diff = $date2 - $date1;
$days = $diff / (60*60*24);
echo ($days . "<br />");
?> (3 Replies)
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I wrote the day calculator also in bash. I would like to now, that is it good so?
#!/bin/bash
datum1=`date -d "1991/1/1" "+%s"`
datum2=`date "+%s"`
diff=$(($datum2-$datum1))
days=$(($diff/(60*60*24)))
echo $days
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Hi Am using Unix Ksh
I have a two date input as
DATE1=02/12/2012
DATE2=30/12/2012
I Need the output as only sunday date
02/12/2012
09/12/2012
16/12/2012
23/12/2012
30/12/2012
can anyone pls help me..
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Gents.
Please can u help.
I would like to calculate the days between two dates.
Example file1 ( previous date)
file1 - Input file
9/29/2010 10195
9/29/2010 1057
2/2/2016 10
2/2/2016 10169
2/2/2016 1057
2/3/2016 10005
2/3/2016 10014
In file2 I add the actual date using this code.... (9 Replies)
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CHAGE(1) User Commands CHAGE(1)
NAME
chage - change user password expiry information
SYNOPSIS
chage [options] LOGIN
DESCRIPTION
The chage command changes the number of days between password changes and the date of the last password change. This information is used by
the system to determine when a user must change his/her password.
OPTIONS
The options which apply to the chage command are:
-d, --lastday LAST_DAY
Set the number of days since January 1st, 1970 when the password was last changed. The date may also be expressed in the format
YYYY-MM-DD (or the format more commonly used in your area).
-E, --expiredate EXPIRE_DATE
Set the date or number of days since January 1, 1970 on which the user's account will no longer be accessible. The date may also be
expressed in the format YYYY-MM-DD (or the format more commonly used in your area). A user whose account is locked must contact the
system administrator before being able to use the system again.
Passing the number -1 as the EXPIRE_DATE will remove an account expiration date.
-h, --help
Display help message and exit.
-I, --inactive INACTIVE
Set the number of days of inactivity after a password has expired before the account is locked. The INACTIVE option is the number of
days of inactivity. A user whose account is locked must contact the system administrator before being able to use the system again.
Passing the number -1 as the INACTIVE will remove an account's inactivity.
-l, --list
Show account aging information.
-m, --mindays MIN_DAYS
Set the minimum number of days between password changes to MIN_DAYS. A value of zero for this field indicates that the user may change
his/her password at any time.
-M, --maxdays MAX_DAYS
Set the maximum number of days during which a password is valid. When MAX_DAYS plus LAST_DAY is less than the current day, the user
will be required to change his/her password before being able to use his/her account. This occurrence can be planned for in advance by
use of the -W option, which provides the user with advance warning.
Passing the number -1 as MAX_DAYS will remove checking a password's validity.
-R, --root CHROOT_DIR
Apply changes in the CHROOT_DIR directory and use the configuration files from the CHROOT_DIR directory.
-W, --warndays WARN_DAYS
Set the number of days of warning before a password change is required. The WARN_DAYS option is the number of days prior to the
password expiring that a user will be warned his/her password is about to expire.
If none of the options are selected, chage operates in an interactive fashion, prompting the user with the current values for all of the
fields. Enter the new value to change the field, or leave the line blank to use the current value. The current value is displayed between a
pair of [ ] marks.
NOTE
The chage program requires a shadow password file to be available.
The chage command is restricted to the root user, except for the -l option, which may be used by an unprivileged user to determine when
his/her password or account is due to expire.
CONFIGURATION
The following configuration variables in /etc/login.defs change the behavior of this tool:
FILES
/etc/passwd
User account information.
/etc/shadow
Secure user account information.
EXIT VALUES
The chage command exits with the following values:
0
success
1
permission denied
2
invalid command syntax
15
can't find the shadow password file
SEE ALSO
passwd(5), shadow(5).
shadow-utils 4.1.5.1 05/25/2012 CHAGE(1)