I forgot to tell you what I am trying to do this on a Windows machine with UnxUtils "installed".
Your right!!!
I will do better in the future to show what I have done.
I'm new to scripting in shell code.
I have tried the following code without any real progress.
The problem is that I want to print to the next white space... not only 15 characters...
/Pierre
---------- Post updated 22-04-10 at 12:47 AM ---------- Previous update was 21-04-10 at 11:15 AM ----------
Hi Again,
Due to the fact that I'm is forced to work with windows I can't get it to work.
I have changed the ' to " and I still donsen't work.
I think it has to be somthing with the windows formating.
Result:
1
1
1
1
1
1
....
/Pierre
edit by bakunin: i edited into the text the code-tags you should have used yourself when posting code or code-snippets. Thanks for doing this yourself from now on.
Hi,
My input has much more lines, but few of them are below
pin(IDF) {
direction : input;
drc_pinsigtype : signal;
pin(SELDIV6) {
direction : input;
drc_pinsigtype : ... (3 Replies)
i have a file which contains alphanumeric data in every line. what i need is the data after certain pattern. the data after the pattern is not of fixed length so i need the data till the space after the pattern.
Input file:
bfdkasfbdfg khffkf lkdhfhdf pattern (datarequired data not required)... (2 Replies)
Hello,
I want to read a CSV file and look for a pattern on each line. If the pattern is found I want to read another portion/column of that line and print that. Can somebody help me in writing it in CSH?
E.g. CSV file has following lines,
1,Elephant,500kg,,,,,
2,Tiger,50kg,,,,,... (4 Replies)
I have this content in file
sshd : ALL : allow
SSHD : all : ALLOW
sshD : All : AllOW
What I need is to print the occurrence of "sshd:all" regardless of the spaces between them and if lower/upper case. So all lines should be printed in output when "grepped" or "printed... (3 Replies)
Hi Gurus, i need your help to create a script the will print a characters after the pattern was found.
Sample lines are below:
My birthday:"1977-16-07", My birthday:"1975-16-07"
My birthday:"1970-16-07".
My patter should be "birthday:", then i want to print the following characters which... (18 Replies)
Using grep I can easily use:
cvs log |grep -iB 10 -A 10 'date: 2013-10-30'
to display search results and 10 lines before and after. How can this be accompished using gawk? (4 Replies)
Hi,
I need help on a complicated file that I am working on. I wanted to extract important info from a very huge file. It is space delimited file. I have hundred thousands of records in this file. An example content of the inputfile as below:-
##
ID Ser402 Old; 23... (2 Replies)
The intended result should be :
PDF converters
'empty line'
gpdftext and pdftotext?xml version="1.0"?>
xml:space="preserve"><note-content version="0.1" xmlns:/tomboy/link" xmlns:size="http://beatniksoftware.com/tomboy/size">PDF converters
gpdftext and pdftotext</note-content>... (9 Replies)
Discussion started by: Klasform
9 Replies
9. Post Here to Contact Site Administrators and Moderators
In file, we have millions of records each of 1000 in length. And at specific position say 800 there is a space, we need to replace it with Character X if the ID in that row starts with 123.
So far i have used the below which is replacing space at that position to X but its not checking for... (3 Replies)
Hi,
I am trying to extract data based on certain conditions. My sample input file as below:-
lnc-2:1 OnePiece tra_law 500 688 1 . . g_id "R792.8417"# tra_law_id "R792.8417.1"# g_line "2.711647"# KM "8.723820"#
lnc-2:1 OnePiece room 500 510 1 . . g_id "R792.8417"# tra_law_id "R792.8417.1"#... (7 Replies)
Discussion started by: bunny_merah19
7 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)