Hi Gurus,
I have a requirement of writting the shell script where it should ask me two values
FND_TOP=/d02/app/oracle/xxx/fnd/11.5.0
CDCRM_TOP=/d02/app/oracle/xxx/cdcrm/11.5.0
and then keep these values stored as variables for the execution of rest of the script.
Because, I have to... (2 Replies)
I am new to unix and the following problem is bugging me.:confused:
var1="hello1"
var2="hello2"
var3="hello3"
counter=1
while
do
echo $var$counter
done
the idea here is to display the value of "var" based on the counter.
I am using the korn shell. I used array here but the... (4 Replies)
Hi All,
Shell is ksh
I've given portion of the script here to explain the problem.
It will accept 2 input parameters .
in_file1=$1
in_file2=$2
outbound_dir=/home/outbound
for i in 1 2
do
eval file$i=$outbound_dir/\$in_file$i
eval echo "filename is \$file$i"
... (4 Replies)
Hello,
so i'm making a script, using dynamic variables and trying to expand them. So far it hasn't worked out too well so it seems that I need some help from you, the elite.
Example:
#!/bin/sh
counter=0
until (($counter>5))
counter2=1
until (($counter2>6)); do
if ;... (5 Replies)
Greetings all,
Been trying to do my Googling and forum searches but can't seem to lock in on a solution.
I have a script that parses a log and collects all the uniq events to a flat file. Some days might have 50 unique events, other days might have 75. (Hence my reference to dynamic.)
... (2 Replies)
Hi all,
I want to dynamically set variables in a bash script. I made a naive attempt in a while loop that hopefully can clarify the idea.
n=0; echo "$lst" | while read p; do n=$(($n+1)); p"$n"="$p"; done
The error message is:
bash: p1=line1: command not found
bash: p2=line2: command... (8 Replies)
Hi ,
i am unable to generate dynamic variables can any one please help me on the below issue
j=1
{record_count_"$j"}=`db2 -xselect substr\(job_name,24\) rec_count from $libname.audit_table_nrt where job_name like \'DATAMART_DEL_RUN%\' and STS_FLAG=\'E\' and seq_no=$i`
echo " record... (3 Replies)
Hi Guys,
I wrote a collection of bash functions years ago and now need to use them again but
I'm getting some error messages when eval tries to expand the variables names.
I recollect that I used the shopt command to set one of the options but I can't quite
remember the command that I... (8 Replies)
Discussion started by: ASGR
8 Replies
LEARN ABOUT PHP
eval
EVAL(3) 1 EVAL(3)eval - Evaluate a string as PHP codeSYNOPSIS
mixed eval (string $code)
DESCRIPTION
Evaluates the given $code as PHP.
Caution
The eval(3) language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged.
If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user
provided data into it without properly validating it beforehand.
PARAMETERS
o $code
- Valid PHP code to be evaluated. The code mustn't be wrapped in opening and closing PHP tags, i.e. 'echo "Hi!";' must be passed
instead of '<? echo "Hi!"; >'. It is still possible to leave and reenter PHP mode though using the appropriate PHP tags, e.g.
'echo "In PHP mode!"; ?>In HTML mode!<? echo "Back in PHP mode!";'. Apart from that the passed code must be valid PHP. This
includes that all statements must be properly terminated using a semicolon. 'echo "Hi!"' for example will cause a parse error,
whereas 'echo "Hi!";' will work. A return statement will immediately terminate the evaluation of the code. The code will be exe-
cuted in the scope of the code calling eval(3). Thus any variables defined or changed in the eval(3) call will remain visible
after it terminates.
RETURN VALUES eval(3) returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. If there is a
parse error in the evaluated code, eval(3) returns FALSE and execution of the following code continues normally. It is not possible to
catch a parse error in eval(3) using set_error_handler(3).
EXAMPLES
Example #1
eval(3) example - simple text merge
<?php
$string = 'cup';
$name = 'coffee';
$str = 'This is a $string with my $name in it.';
echo $str. "
";
eval("$str = "$str";");
echo $str. "
";
?>
The above example will output:
This is a $string with my $name in it.
This is a cup with my coffee in it.
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
Tip
As with anything that outputs its result directly to the browser, the output-control functions can be used to capture the output of
this function, and save it in a string (for example).
Note
In case of a fatal error in the evaluated code, the whole script exits.
SEE ALSO call_user_func(3).
PHP Documentation Group EVAL(3)