Sponsored Content
Operating Systems AIX Replace string with asterisk(*) in variable Post 302414225 by Vaddadi on Monday 19th of April 2010 02:04:44 PM
Old 04-19-2010
Thanks ... tried set -f & set +f , but it didn't work ..
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Replace string in a file w/ a variable value

I am trying to replace the default home page for several mac user accounts, I wrote a script that will hunt the files down and replace them with a pre-configured set. The problem I am having is that the download destination path for the browser is hard coded into a .plist (text config file) file... (5 Replies)
Discussion started by: tret
5 Replies

2. Shell Programming and Scripting

Using sed to replace a string in file with a string in a variable that contains spaces

Hi, i call my shell like: my_shell "my project name" my script: #!/bin/bash -vx projectname=$1 sed s/'PROJECT_NAME ='/'PROJECT_NAME = '$projectname/ <test_config_doxy >temp cp temp test_config_doxy the following error occurres: sed s/'PROJECT_NAME ... (2 Replies)
Discussion started by: vivelafete
2 Replies

3. Shell Programming and Scripting

Replace string in file with a variable value

Hi Fellows, I am new to shell, please help we me out in this.. i have file which some lines like this.. $$param1='12-jan-2011' $$param2='14-jan-2011' $$param3='30-jan-2011' . . .....so on.. I want to change $$param3 to '31-dec-2011'. i have variable which is storing(30-jan-2011 this... (1 Reply)
Discussion started by: victor369
1 Replies

4. Shell Programming and Scripting

replace (sed?) a string in file with multiple lines (string) from variable

Can someone tell me how I can do this? e.g: a=$(echo -e wert trewt ertert ertert ertert erttert erterte rterter tertertert ert) How do i replace the STRING with $a? I try this: sed -i 's/STRING/'"$a"'/g' filename.ext but this don' t work (2 Replies)
Discussion started by: jforce
2 Replies

5. Shell Programming and Scripting

How to replace a string with a variable in a file using sed?

I have a file having some text like: PATH_ABC=/user/myLocation I have to replace "/user/myLocation" with a session variable say, $REPLACE_PATH, where $REPLACE_PATH=/user/myReplaceLocation The following sed command is not working. It is writing PATH_ABC=$REPLACE_PATH in the file ... (2 Replies)
Discussion started by: SKhan
2 Replies

6. Shell Programming and Scripting

How to replace a string to asterisk?

Hi, I would like to ask for you idea on how to convert a string to "*". say password and username. I have a shell script that will promt the user to enter username and password. This will be passed to sqlplus command. echo "Please enter user name" read USERNAME echo... (2 Replies)
Discussion started by: reignangel2003
2 Replies

7. Shell Programming and Scripting

Need to use asterisk in variable

Hi All, I am having a challange to pass the asterisk in the variable. Basically, I am writing a shell script to check if a marker file exists but when I am assigning the varialbe it cannot use the wildcard asterisk as expected, therefore, my program is always outputs "Marker file is not... (4 Replies)
Discussion started by: express14
4 Replies

8. UNIX for Dummies Questions & Answers

Replace variable string with text

Hi All, Hoping someone can help.... I am trying to work out how I can ammend a log file to remove variable strings in order to remove confidential information which I cant pass on. As an example I have used phone numbers. A large log file contains multiple lines containing something like the... (6 Replies)
Discussion started by: mutley2202
6 Replies

9. Shell Programming and Scripting

Replace substring from a string variable

Hi, Wish to remove "DR-" from the string variable (var). var="DR-SERVER1" var=`echo $var | sed -e 's/DR-//g'` echo "$var" Expected Output: However, I get the below error: Can you please suggest. (4 Replies)
Discussion started by: mohtashims
4 Replies

10. Shell Programming and Scripting

How to replace string in variable?

Hello, I have simple while and for loops in a shell script and I would like to replace some characters in COL2 when I run it. I am on ubuntu 14.04 while read COL1 COL2 COL3 COL4 do name=$COL2 #cat $name | sed -i "s|_| |g" $name for i in $COL3 $COL4 do some codes ...... run $i b="$name"... (11 Replies)
Discussion started by: baris35
11 Replies
Test::Without::Module(3)				User Contributed Perl Documentation				  Test::Without::Module(3)

NAME
Test::Without::Module - Test fallback behaviour in absence of modules SYNOPSIS
use Test::Without::Module qw( My::Module ); # Now, loading of My::Module fails : eval { require My::Module; }; warn $@ if $@; # Now it works again eval q{ no Test::Without::Module qw( My::Module ) }; eval { require My::Module; }; print "Found My::Module" unless $@; DESCRIPTION
This module allows you to deliberately hide modules from a program even though they are installed. This is mostly useful for testing modules that have a fallback when a certain dependency module is not installed. EXPORT None. All magic is done via "use Test::Without::Module LIST" and "no Test::Without::Module LIST". Test::Without::Module::get_forbidden_list This function returns a reference to a copy of the current hash of forbidden modules or an empty hash if none are currently forbidden. This is convenient if you are testing and/or debugging this module. ONE LINER
A neat trick for using this module from the command line was mentioned to me by NUFFIN and by Jerrad Pierce: perl -MTest::Without::Module=Some::Module -w -Iblib/lib t/SomeModule.t That way, you can easily see how your module or test file behaves when a certain module is unavailable. BUGS
o There is no lexical scoping CREDITS
Much improvement must be thanked to Aristotle from PerlMonks, he pointed me to a much less convoluted way to fake a module at <http://www.perlmonks.org/index.pl?node=192635>. I also discussed with him an even more elegant way of overriding CORE::GLOBAL::require, but the parsing of the overridden subroutine didn't work out the way I wanted it - CORE::require didn't recognize barewords as such anymore. NUFFIN and Jerrad Pierce pointed out the convenient use from the command line to interactively watch the behaviour of the test suite and module in absence of a module. AUTHOR
Copyright (c) 2003-2009 Max Maischein, <corion@cpan.org> LICENSE
This module is released under the same terms as Perl itself. SEE ALSO
Devel::Hide, Acme::Intraweb, PAR, perlfunc perl v5.16.3 2009-01-18 Test::Without::Module(3)
All times are GMT -4. The time now is 03:32 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy