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Top Forums UNIX for Dummies Questions & Answers Read directory files and count number of lines Post 302412078 by jl487 on Sunday 11th of April 2010 02:55:47 PM
Old 04-11-2010
Read directory files and count number of lines

Hello, I'm trying to create a BASH file that can read all the files in my working directory and tell me how many words and lines are in that file. I wrote the following code:

Code:
FILES="*"
for f in "$FILES"
do
  echo -e `wc -l -w $f`

done

My issue is that my file is outputting in one continuous line. How can I make it so that it shows like this:

FILE1 43 251
FILE2 5 21
FILE3 157 187
etc...

Thanks!

Last edited by jl487; 04-11-2010 at 04:01 PM..
 

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OCAMLWC(1)						      General Commands Manual							OCAMLWC(1)

NAME
ocamlwc - count the lines of code and comments in OCaml sources SYNOPSIS
ocamlwc [options] [files] DESCRIPTION
ocamlwc is a program to count the number of lines of code and documentation in OCaml sources. It assumes its input to be lexically well- formed. If no files are given, then ocamlwc reads from stdin. The first column of the output lists the number of source lines of code, the second column the number of lines of documentation, and the third the respective filename. If ocamlwc acts on more than one file, then it prints a total in the last line. OPTIONS
-p Print percentage of documentation (in an additional column after the filename). -c Print only the code size, i.e., omit the documentation column. -e (everything) Do not skip headers. A header is the first comment in a file. -a (all) Do not skip generated files. foo.ml is a generated file if one of foo.mll, foo.mly, or foo.ml4 is amongst the given files. foo.mli is a generated file if foo.mly is amongst the given files. -h Print short usage information. AUTHOR
ocamlwc was written by Jean-Christophe Filliatre <Jean-Christophe.Filliatre@lri.fr>. This manual page was written by Georg Neis <gn@oglaroon.de>. January 2, 2007 OCAMLWC(1)
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