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Top Forums Shell Programming and Scripting Extracting a portion of data from a very large tab delimited text file Post 302412060 by Franklin52 on Sunday 11th of April 2010 11:36:32 AM
Old 04-11-2010
Quote:
Originally Posted by Lucky Ali
Hi All

I wanted to know how to effectively delete some columns in a large tab delimited file.

I have a file that contains 5 columns and almost 100,000 rows

Code:
3456 f g t t
3456 g h
456   f  h
4567 f g h z
345   f g
567   h j k l

This is a very large data file and tab delimited.

I need to extract the rows that have values in all the 5 columns. At present, there are several rows that contain only 3 values.

please let me know the best way to extract the rows with all 5 values

Thanks.
LA
Code:
awk 'NF==5' file > newfile

 

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pfscut(1)						      General Commands Manual							 pfscut(1)

NAME
pfscut - Extract a rectangle out of a frame in PFS stream SYNOPSIS
pfscut [--left <columns>] [--right <columns>] [--top <rows>] [--bottom <rows>] [--width <new_width>] [--height <new_height>] [--help] [x_ul y_ul x_br y_br] DESCRIPTION
Extract a rectangle out of each frame in PFS stream. You can either specify x and y coordinates of upper left and lower right corner (the coordinates start with 0 and rise in the left-to-right and up-to-botton directions) or give a combination of the options listed below. OPTIONS
--left <columns>, -l <columns> Number of columns to be cut out from the left edge of an image. --right <columns>, -r <columns> Number of columns to be cut out from the right edge of an image. --top <rows>, -t <rows> Number of rows to be cut out from the top edge of an image. --bottom <rows>, -b <rows> Number of rows to be cut out from the bottom edge of an image. --width <new_width>, -W <new_width> Width of an output image. Note that --width can be mixed with either --left or --right option. --height <new_height>, -H <new_height> Height of an output image. Note that --height can be mixed with either --top or --bottom option. --help, -h Print a list of commandline options. EXAMPLES
pfsin image.hdr | pfscut --left 20 --top 5 | pfsout out.hdr Cut out 20 columns from the left and 5 rows from the top edge of image.hdr and save frame as out.hdr. pfsin image.hdr | pfscut --left 20 --width 400 | pfsout out.hdr Cut out 20 columns from the left edge of image.hdr, and create output image 400 pixels in width. pfsin image.hdr | pfscut 0 0 511 511 | pfsout out.hdr Cut left-upper part of the image of the size 512x512 (note that coordinates start with 0 and 512 is the last row/column that is included in the resulting image). SEE ALSO pfsin(1) pfsout(1) BUGS
Please report bugs and comments to Dorota Zdrojewska <dzdrojewska@wi.ps.pl>. pfscut(1)
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