hey all, me again....having a problem with my code, where I essentially am trying to show a menu, have the user select an option (from 1 to 5), then display which selection they picked...
Code:
#!/bin/bash
# A LIST OF THE ERROR MESSAGES AND THE PROPER SYNTAX:
error_0="Correct amount of arguments provided."
error_10="Error: No arguments present at all."
error_11="You must input the first argument."
error_12="Error: Expecting \"-i\" for the first argument."
error_13="You must enter a filename for the second argument."
error_14="$2 does not exist. Please enter a real file."
error_15="You must enter a third argument."
error_16="Error: Expecting \"-o\" for the third argument."
error_17="You must enter a filename for the fourth argument."
error_18="Error: Too many arguments."
error_19="No overwrite selected...exiting program"
proper="Usage: ./Lab_14.sh -i <infile> -o <outfile> \n \n-i <infile> The filename containing the existing data. \n-o <outfile> The filename you want the output"
hit_enter="Press <ENTER> to continue"
ow="1"
menu="1"
menu_choice="Menu option "$choice" selected"
menu_content="\n MAIN MENU \n --------- \n 1) Menu Option 1 \n 2) Menu Option 2 \n 3) Menu Option 3 \n 4) Menu Option 4 \n \n 5) Quit \n \n Please enter a menu option:"
#CHECK IF THERE ARE NO ARGUMENTS PRESENT:
if [ "$#" == "0" ] ;then
echo
echo $error_10
echo
echo -e $proper
echo
exit 10
fi
#CHECK IF FIRST ARGUMENT IS BLANK:
if [ "$1" == "" ] ;then
echo
echo $error_11
echo
echo -e $proper
echo
exit 11
fi
#CHECK IF FIRST ARGUMENT IS -i:
if [ "$1" != "-i" ] ;then
echo
echo $error_12
echo
echo -e $proper
echo
exit 12
fi
#CHECK IF SECOND ARGUMENT IS BLANK:
if [ "$2" == "" ] ;then
echo
echo $error_13
echo
echo -e $proper
echo
exit 13
fi
#CHECK IF SECOND ARGUMENT (INPUT FILENAME) EXISTS:
if [ ! -e "$2" ] ;then
echo
echo $error_14
echo
echo -e $proper
echo
exit 14
fi
#CHECK IF THIRD ARGUMENT IS BLANK:
if [ "$3" == "" ] ;then
echo
echo $error_15
echo
echo -e $proper
echo
exit 15
fi
#CHECK IF THIRD ARGUMENT IS -o:
if [ "$3" != "-o" ] ;then
echo
echo $error_16
echo
echo -e $proper
echo
exit 16
fi
#CHECK IF FOURTH ARGUMENT IS BLANK:
if [ "$4" == "" ] ;then
echo
echo $error_17
echo
echo -e $proper
echo
exit 17
fi
#CHECK IF THERE ARE TOO MANY (MORE THAN 4) ARGUMENTS:
if [ "$#" -ge "5" ] ;then
echo
echo $error_18
echo
echo -e $proper
echo
exit 18
fi
#IF FOURTH FILE EXISTS, ASK IF USER WANTS IT OVERWRITTEN:
if [ "$1" == "-i" ] && [ -e "$2" ] && [ "$3" == "-o" ] && [ -e "$4" ] ;then
while [ $ow != "5" ]
do
echo
echo "File \"$4\" exists already"
echo -n "Do you wish to overwrite file contents (y/n)?"
read overwrite
case $overwrite in
y)
ow="5"
clear
while [ $menu != "quit" ]
do
echo
echo -en $menu_content
read choice
case $choice in
1)
echo
echo $menu_choice
echo $hit_enter
read continue
clear
;;
2)
echo
echo $menu_choice
echo $hit_enter
read continue
clear
;;
3)
echo
echo $menu_choice
echo $hit_enter
read continue
clear
;;
4)
echo
echo $menu_choice
echo $hit_enter
read continue
clear
;;
5)
echo
echo $menu_choice
echo $hit_enter
read continue
clear
menu="quit"
exit 0
;;
*)
echo
echo "Try picking an option from the menu"
echo $hit_enter
read continue
clear
;;
esac
done
;;
n)
echo
echo $error_19
exit 19
;;
*)
echo "Please select y or n"
echo $hit_enter
read continue
;;
esac
done
fi
#IF FOURTH FILE DOES NOT EXIST, GO STRAIGHT TO MENU:
if [ "$1" == "-i" ] && [ -e "$2" ] && [ "$3" == "-o" ] && [ ! -e "$4" ] ;then
clear
while [ $menu != "quit" ]
do
echo
echo -en $menu_content
read choice
case $choice in
1)
echo
echo $menu_choice
echo $hit_enter
read continue
clear
;;
2)
echo
echo $menu_choice
echo $hit_enter
read continue
clear
;;
3)
echo
echo $menu_choice
echo $hit_enter
read continue
clear
;;
4)
echo
echo $menu_choice
echo $hit_enter
read continue
clear
;;
5)
echo
echo $menu_choice
echo $hit_enter
read continue
clear
menu="quit"
exit 0
;;
*)
echo
echo "Try picking an option from the menu"
echo $hit_enter
read continue
clear
;;
esac
done
fi
I bolded/italicized/underlined the problem
Whenever I make a choice in the menu, rather then saying "Menu option 1 selected" it just says "menu option selected"
Hi there all
I got the following
I got multiple arrays named for example
STAT_AAAA
STAT_AAAB
STAT_AAAC
STAT_AAAD
Now what I want I have chosen an option in a menu to select 1
but I dont want to write for all the same thing so I made it a signle one
now what I want is to get
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