Hello people
I need to find a way to generate a file that contains the names of all *.jpg files that were generated after a specific date
The search should start in my current folder and recursively search inner folders
It would be best to list the file names one below the other in the output... (3 Replies)
Dear Masters,
Is there an easy way to generate a random list from a give list of names? Let's say, I have a file containing 15000 city name of world(spreadsheet, names in the first column), I would like to randomly pick up 50 cities each time for total 1000 picks. Or doesn't anyone know a... (3 Replies)
Hi,
I want to write a script which can generate a kill list for killing process, program name start with f60.., which have been running for more than 8 hours, the list output should looks like:
kill -9 4444176
kill -9 4674520
kill -9 4454180
kill -9 4994523
Can anyone help how to write... (10 Replies)
Hi
Please help me to resolve the below query.
My shell script has generated a file output.file like below
********************************
DROP TABLE GPS_CONTACT_DETAILS
DB20000I The SQL command completed successfully.
CREATE TABLE GPS_CONTACT_DETAILS ( CONTACT_ID ... (8 Replies)
How can I generate a list of numbers and place all of these numbers in a line-by-line into a file.
I am new to scripting actually.
0501000000 to 0509999999
i.e.
0501000000
0501000001
......
0509999999
set 02
0551000000 to 0559999999
i.e.
0551000000
0551000001
......
0559999999
... (3 Replies)
Is there a tool that can diff a directory and generate a change list of files in that directory based on a previous snapshot on the directory?
For example
/etc/a.txt:changed
/etc/b.txt:removed
/etc/c.txt:added
Thanks! (1 Reply)
I copied all JPEGs from my laptop to an external drive using
find . -name "*.jpg" -exec cp '{}' ./media/Backup/pictures \;
And then deleted all of them from my laptop.
Now, I realize that I need the folder path of all the original JPEGs as the path has the important information.
I dont... (1 Reply)
I manage an AIX OS 7.1 system on IBM Power 770.
I want to find out which directories/folders a particular user has read/write access to. How can I cleanly create a list of all directories on the system that a user has access to.. Does this make sense?
Thanks in Advance, NEWB:rolleyes: (3 Replies)
Heyas
I want to list passed arguments and make an incrementing 'marker'.
That 'marker' should be a letter between a-z, in proper order.
I'm not aware of a seq pendant, so i tried it with this:
C=141
list=""
while ];do
printf \\$C
list+=" \\$C"
C=$((C+1))
done
echo... (3 Replies)
Perl::Critic::Policy::ValuesAndExpressions::ProhibitCommUseraContriPerl::Critic::Policy::ValuesAndExpressions::ProhibitCommaSeparatedStatements(3)NAME
Perl::Critic::Policy::ValuesAndExpressions::ProhibitCommaSeparatedStatements - Don't use the comma operator as a statement separator.
AFFILIATION
This Policy is part of the core Perl::Critic distribution.
DESCRIPTION
Perl's comma statement separator has really low precedence, which leads to code that looks like it's using the comma list element separator
not actually doing so. Conway suggests that the statement separator not be used in order to prevent this situation.
The confusion that the statement separator causes is primarily due to the assignment operators having higher precedence.
For example, trying to combine two arrays into another like this won't work:
@x = @y, @z;
because it is equivalent to
@x = @y;
@z;
Conversely, there are the built-in functions, like "print", that normally force the rest of the statement into list context, but don't when
called like a subroutine.
This is not likely to produce what is intended:
print join q{, }, 2, 3, 5, 7, ": the single-digit primes.
";
The obvious fix is to add parentheses. Placing them like
print join( q{, }, 2, 3, 5, 7 ), ": the single-digit primes.
";
will work, but
print ( join q{, }, 2, 3, 5, 7 ), ": the single-digit primes.
";
will not, because it is equivalent to
print( join q{, }, 2, 3, 5, 7 );
": the single-digit primes.
";
CONFIGURATION
This policy can be configured to allow the last statement in a "map" or "grep" block to be comma separated. This is done via the
"allow_last_statement_to_be_comma_separated_in_map_and_grep" option like so:
[ValuesAndExpressions::ProhibitCommaSeparatedStatements]
allow_last_statement_to_be_comma_separated_in_map_and_grep = 1
With this option off (the default), the following code violates this policy.
%hash = map {$_, 1} @list;
With this option on, this statement is allowed. Even if this option is off, using a fat comma "=>" works, but that forces stringification
on the first value, which may not be what you want.
BUGS
Needs to check for "scalar( something, something )".
AUTHOR
Elliot Shank "<perl@galumph.com>"
COPYRIGHT
Copyright (c) 2007-2011 Elliot Shank.
This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself. The full text of this license
can be found in the LICENSE file included with this module.
perl v5.16.3Perl::Critic::Policy::ValuesAndExpressions::ProhibitCommaSeparatedStatements(3)