03-18-2010
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Hi,
I want to know how to change this string to date format
20061102122042 to 02-11-2006 12:20:42
or 02-Nov-2006 12:20:42
Please let me know at the earliest.Thanks in advance.
Regards,
Preetham R. (3 Replies)
Discussion started by: preethgideon
3 Replies
2. UNIX for Advanced & Expert Users
I know the command date +"%Y%m%d" can change today's date to digit format as below .
$date +"%Y%m%d"
20071217
it works fine .
now I want to do it back . If I have a file like below, (in the file , there are three lines, and each line have ; sign , after the ; sign is the date ) , I... (4 Replies)
Discussion started by: ust
4 Replies
3. Shell Programming and Scripting
Hi All,
this is my second post, last post reply was very helpful.
I have a data that has date in DD/MM/YYYY (07/11/2008) format i want to replace the backslash by a dot(.) so that my awk script can read it inside the C shell script that i have written.
i want to change 07/11/2008 to... (3 Replies)
Discussion started by: asirohi
3 Replies
4. Solaris
dear members,
ls -l
drwxr-xr-x 40 root sys 1024 Jul 11 22:19 usr
drwxr-xr-x 43 root sys 1024 Feb 1 2009 var
i am using solaris 10
is that possibe to do
drwxr-xr-x 40 root sys 1024 25-08-2009 22:19 usr
drwxr-xr-x 43 root sys ... (4 Replies)
Discussion started by: hosney00ux
4 Replies
5. Shell Programming and Scripting
Hi I have a date format in a variable as Mon Jan 11 03:35:59 2010. how do i change it to YYYYMMDD format (3 Replies)
Discussion started by: keerthan
3 Replies
6. Shell Programming and Scripting
Hi,
Please can I have some command to get yesterday in YYMMDD format?
This will be used in ksh
Thanks, (2 Replies)
Discussion started by: smalya
2 Replies
7. Shell Programming and Scripting
Dear Friends,
Need your help once again,
I have a variable ( e.g. ${i}) whoch has date in MM/DD/YYYY (E.g. 12/31/2011) format.
I want to change it to DD/MM/YYYY (e.g. 31/12/2011) format.
Request you to guide me as we are unable to do the same.
Thanks in advance
Anu. (1 Reply)
Discussion started by: anushree.a
1 Replies
8. Shell Programming and Scripting
Hi,
I have the variable "$date_update" in that form:
2011-12-31T13:00:09Z and I would like to change it to
31/12/2011 13:00:09 (Date and Time separated by a blank).
Does anyone has a simple solution for that? (using Korn Shell)
Cheers
Jurgen (4 Replies)
Discussion started by: jurgen
4 Replies
9. Shell Programming and Scripting
Hi all,
I have a file that every line starts with the date and time. The format is like YYYYMMDDHHMM and I woulk like to change it to MM/DD/YY<space>HH:MM.
I tried to figure out a way to do it with sed, but I don't know how I could reorganize the digits of the first format. Does anyone have any... (1 Reply)
Discussion started by: geovas
1 Replies
10. Shell Programming and Scripting
Hi,
I was looking for a script to change the date from one format to other. A search in the forum gave me the below script as a result.
#! /bin/ksh
format=YYYYMMDD
YEAR=${format%????}
DAY=${format#??????}
MON=${format#$YEAR}
MON=${MON%$DAY}
echo $MON/$DAY/$YEAR
I got it... (2 Replies)
Discussion started by: prithvirao17
2 Replies
LEARN ABOUT DEBIAN
jifty::manual::tutorialrest
Jifty::Manual::TutorialRest(3pm) User Contributed Perl Documentation Jifty::Manual::TutorialRest(3pm)
NAME
Jifty::Manual::TutorialRest - Web Services
DESCRIPTION
This builds on Jifty::Manual::Tutorial, so make sure you have a running jifty that roughly resembles the step-by-step from there.
SETUP
You must add this to your site_config.yml
framework:
Plugins:
- REST: {}
See Jifty::Plugin::REST.
The commands assume that you have LWP installed with the GET alias. If not, you'll need to use the longhand lwp-request -m GET, or curl,
or your browser.
help
Make sure it is working:
$ GET http://localhost:8888/=/help
Accessing resources:
...
You should see some text describing the services, not html (that's longhand for 404.) Check the config and restart the server.
GET
Just list the models.
$ GET http://localhost:8888/=/model.yml
---
- MyWeblog.Model.Post
List the Post schema.
$ GET http://localhost:8888/=/model/Post.yml
---
body:
label: Content
name: body
readable: 1
sort_order: 1
type: text
writable: 1
id:
mandatory: 1
name: id
readable: 1
type: serial
writable: 0
title:
default: Untitled post
label: Title
name: title
readable: 1
sort_order: 0
type: text
writable: 1
You did make some posts, right?
$ GET http://localhost:8888/=/model/Post/id.yml
---
- 1
- 2
Dump the data:
$ GET http://localhost:8888/=/model/Post/id/1.yml
---
body: 'This is my post, the content of which is this, which is mine.'
id: 1
title: my first post
$ GET http://localhost:8888/=/model/Post/id/2.yml
---
body: "Content of another post. Got to go, the cat's on fire."
id: 2
title: post deux
POST
TODO not working
Actually, it looks like it is not supposed to work this way. Why not?
$ echo '---
body: "A post via web services"
id: 3
title: "posting from the command-line"
' | lwp-request -m POST http://localhost:8888/=/model/Post.yml
POST http://localhost:8888/=/model/Post/id/3.yml --> 404 Not Found
PUT
TODO not working
$ echo '---
title: "posting from the cli"
' | lwp-request -m PUT http://localhost:8888/=/model/Post/3.yml
500 Can't read entity body: Connection reset by peer
DELETE
$ lwp-request -m DELETE http://localhost:8888/=/model/Post/id/3.yml
---
content: {}
error: ~
field_errors: {}
field_warnings: {}
message: Deleted
success: 1
perl v5.14.2 2010-09-25 Jifty::Manual::TutorialRest(3pm)