Sponsored Content
Top Forums Shell Programming and Scripting how to get what date was 28 days ago of the current system date IN UNIX Post 302405216 by kandi.reddy on Thursday 18th of March 2010 06:53:08 AM
Old 03-18-2010
date +%Y-%m-%d --date='28 day ago'

With the above command it will give the current date...

I need what date it was 28 days ago from the todays date.
kandi.reddy
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

How to find a date which is 7 days past when given current date

hii all. I have to get the date of the 7th day past from the current date. if i give the current date as sep 3 then i must get the date as 27th of august. can we get the values from the "cal" command. cal | awk '{print $2}' will this type of command work. actually my need is if today is... (17 Replies)
Discussion started by: ladtony
17 Replies

2. Shell Programming and Scripting

Date after 5 days from current date in YYYYMMDD format

Hello Experts, How do i get date after 5 days from current date in YYYYMMDD format? How do you compare date in YYYYMMDD format? Thanks (8 Replies)
Discussion started by: needyourhelp10
8 Replies

3. Shell Programming and Scripting

Date One Week Ago From Given Date, Not From Current Date

Hi all, I've used various scripts in the past to work out the date last week from the current date, however I now have a need to work out the date 1 week from a given date. So for example, if I have a date of the 23rd July 2010, I would like a script that can work out that one week back was... (4 Replies)
Discussion started by: Donkey25
4 Replies

4. Shell Programming and Scripting

How to Get 60 days Old date from current date in KSH script

Hi i am writing a cron job. so for it i need the 60 days old date form current date in variable. Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27. i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
Discussion started by: Himanshu_soni
3 Replies

5. Shell Programming and Scripting

Number of days between the current date and user defined date

I am trying to find out the number of days between the current date and user defined date. I took reference from here for the date2jd() function. Modified the function according to my requirement. But its not working properly. Original code from here is working fine. #!/bin/sh... (1 Reply)
Discussion started by: hiten.r.chauhan
1 Replies

6. Shell Programming and Scripting

How to display a date, 30 days from the current date?

Well guys, I know the right syntax for displaying the current date is $(date). However, I am planning to send emails to some customers which displays their subscription date, and then the expiry. The expiry being 30 days from the current date. What would the right syntax be? (6 Replies)
Discussion started by: xxxx
6 Replies

7. Shell Programming and Scripting

Seven days past date from current date

hi all.. i want 2 know how 2 find 7days past date from current date.. when i used set datetime = `date '+%m%d%y'` i got 060613.. i just want to know hw to get 053013.. i tried using date functions but couldnt get it :( i use c shell and there is no chance that i can change that ..... (3 Replies)
Discussion started by: Rahul619
3 Replies

8. UNIX for Beginners Questions & Answers

Subscribers with Date 90 days older than current date

I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date. Below command is used for this purpose: cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
Discussion started by: dia
1 Replies

9. Shell Programming and Scripting

Get a given date and subtract it to 5 days ago

Hi all, I have been researching to obtain SSL certification expiry for most of our webistes. For some cases, some hosts where not directly accessible so i finally got a solution working with curl using my proxy. This lists the expiry date which i'm finally looking for. # curl --proxy... (4 Replies)
Discussion started by: nms
4 Replies

10. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
DATETIME.MODIFY(3)							 1							DATETIME.MODIFY(3)

DateTime::modify - Alters the timestamp

       Object oriented style

SYNOPSIS
public DateTime DateTime::modify (string $modify) DESCRIPTION
Procedural style DateTime date_modify (DateTime $object, string $modify) Alter the timestamp of a DateTime object by incrementing or decrementing in a format accepted by strtotime(3). PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $modify -A date/time string. Valid formats are explained in Date and Time Formats. RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.3.6 | | | | | | | Absolute date/time statements now take effect. | | | Previously, only relative parts were used. | | | | | 5.3.0 | | | | | | | Changed the return value on success from NULL to | | | DateTime. | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 DateTime.modify(3) example Object oriented style <?php $date = new DateTime('2006-12-12'); $date->modify('+1 day'); echo $date->format('Y-m-d'); ?> Procedural style <?php $date = date_create('2006-12-12'); date_modify($date, '+1 day'); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2006-12-13 Example #2 Beware when adding or subtracting months <?php $date = new DateTime('2000-12-31'); $date->modify('+1 month'); echo $date->format('Y-m-d') . " "; $date->modify('+1 month'); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-01-31 2001-03-03 SEE ALSO
strtotime(3), DateTime.add(3), DateTime.sub(3), DateTime.setDate(3), DateTime.setISODate(3), DateTime.setTime(3), DateTime.setTimes- tamp(3). PHP Documentation Group DATETIME.MODIFY(3)
All times are GMT -4. The time now is 09:20 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy