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Top Forums Shell Programming and Scripting Missing Assigned Variable within logic operator Post 302403518 by sexyTrojan on Friday 12th of March 2010 07:25:20 PM
Old 03-12-2010
Missing Assigned Variable within logic operator

Hey ,

I'm trying to perform the following command, however it cannot read the variable assigned earlier. I'm not sure why this happen. Please help thanks

Code:
while :
do
echo "what's ur name? (if none just press [ENTER])"
read name
changeName = echo $name | sed "s/on/ey/"
echo $changeName  #this variable still can be read
if [ -z $name ]; then
 echo "you don't have a name goodbye"
 exit 0
else
 echo "your name will change from: $name to $changeName" #now changeName cannot be read why?
fi
done

 

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PARSE_STR(3)								 1							      PARSE_STR(3)

parse_str - Parses the string into variables

SYNOPSIS
void parse_str (string $str, [array &$arr]) DESCRIPTION
Parses $str as if it were the query string passed via a URL and sets variables in the current scope. Note To get the current QUERY_STRING, you may use the variable $_SERVER['QUERY_STRING']. Also, you may want to read the section on vari- ables from external sources. Note The magic_quotes_gpc setting affects the output of this function, as parse_str(3) uses the same mechanism that PHP uses to populate the $_GET, $_POST, etc. variables. PARAMETERS
o $str - The input string. o $arr - If the second parameter $arr is present, variables are stored in this variable as array elements instead. RETURN VALUES
No value is returned. EXAMPLES
Example #1 Using parse_str(3) <?php $str = "first=value&arr[]=foo+bar&arr[]=baz"; parse_str($str); echo $first; // value echo $arr[0]; // foo bar echo $arr[1]; // baz parse_str($str, $output); echo $output['first']; // value echo $output['arr'][0]; // foo bar echo $output['arr'][1]; // baz ?> SEE ALSO
parse_url(3), pathinfo(3), http_build_query(3), get_magic_quotes_gpc(3), urldecode(3). PHP Documentation Group PARSE_STR(3)
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