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Top Forums UNIX for Dummies Questions & Answers Display lines not starts with # Post 302403325 by murugaperumal on Friday 12th of March 2010 05:29:35 AM
Old 03-12-2010
If you put the ^ symbol inside the character class, it will not negate the pattern. It means , match the patter starting with. So the following code is not at all work.

Code:
grep [^#] file

Instead of that you should use the following code
Code:
grep ^[^#] file

Here the symbol ^ outside of the character class negate the pattern. The symbol ^ Inside character class represent the starting.
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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