Using bash, I'm trying to read a .properties file (name=value pairs), assigning an indirect variable reference for each line in the file.
The trick is that a property's value string may contain the name of a property that occurred earlier in the file, and I want the name of the 1st property to... (5 Replies)
The construct ${#parameter} returns the number of characters in the parameter and ${!parameter} specifies an indirect variable. My question is: How do I combine these two. What I want is ${#!parameter} but this gives an error.
Of course I can use:
dummy=${!parameter}
${#dummy}
but that's a... (0 Replies)
Hi all,
I have a variable say var1 (output from somewhere, which I can't change)which store something like this:
echo $var1
name=fred
age=25
address="123 abc"
password=pass1234
how can I make the variable $name, $age, $address and $password contain the info?
I mean do this in a... (1 Reply)
Hi
I have variable A_B=alpha
also var1="A"
var2="B"
I want to retrieve the value alpha using var1 and var2 , somthing like
echo ${${var1}_${var2}} that works. Obviously this is receiving syntax
error (6 Replies)
Hello,
is there a kind soul who can answer me, does the SH support double substitution known as indirect expansion similar to BASH? The syntax for bash is ${!var}.
For instance in bash I can write something like this:
VAR="value"
REF_VAR="VAR"
echo ${!REF_VAR}
and get the "value"... (1 Reply)
I have a file with two columns of numbers (member IDs):
1 1
2 1
3 1
4 2
5 4
6 1
7 5
8 3
9 2
Think of column 1 as the referee and column 2 as the referrer.
Is there a good way to backtrack who referred who? I would like an output, for this example here to be:
1 1
2 1
3 1
4 2 1 (2 Replies)
Hi all,
Hereby wish to have your advise for below:
Main concept is
I intend to get current directory of my script file.
This script file will be copied to /etc/init.d.
A string in this copy will be replaced with current directory value.
Below is original script file:
... (6 Replies)
Hello,
I've spent hours this morning reading various past forum posts and documentation pages but I can't find exactly what I need.
I'm trying to call a variable with a variable in the name without having to make a third variable.
For example:
path=AB
legAB=50
leg$path
I want to... (8 Replies)
Hi,
I need a ksh script to replace indirect directory references in an .ini file with a env variable using sed or awk.
The .ini file is for example as such:
A=..
B=../
C=../..
D=../../
E=../bin
F=../../bin
G=../../bin/xml
H=../../bin/xml/
Need to replace an instance of .. or... (2 Replies)
Discussion started by: andyatit
2 Replies
LEARN ABOUT DEBIAN
addbddvar
ADDBDDVAR(3) BDD FUNCTIONS ADDBDDVAR(3)NAME
addbddvar - adds a new variable in the bdd system.
ORIGIN
This software belongs to the ALLIANCE CAD SYSTEM developed by the ASIM team at LIP6 laboratory of Universite Pierre et Marie CURIE, in
Paris, France.
Web : http://asim.lip6.fr/recherche/alliance/
E-mail : alliance-users@asim.lip6.fr
SYNOPSYS
#include "bdd101.h"
bddnode *addbddvar( BddSystem, Variable )
bddsystem *BddSystem;
bddvar Variable;
PARAMETERS
BddSystem The bdd system.
Variable The variable number.
DESCRIPTION
addbddvar creates a new variable, with the number Variable, in the bdd system BddSystem. If a null pointer is given, the default bdd sys-
tem is used.
RETURN VALUE
addbddvar returns a pointer to the bdd node of the new variable.
ERRORS
"no more variables, error !"
There is no variable number left.
"variable xxx out of range, error !"
The Variable parameter must be less or equal to the BddSystem->NUMBER_VAR field.
EXAMPLE
#include "bdd101.h"
bddsystem *BddSystem;
bddnode *BddNode;
BddSystem = createbddsystem( 100, 1000, 100, 50000 );
BddNode = addbddvar( (bddsystem *)0, 0 );
destroybddsystem( (bddsystem *)0 );
SEE ALSO bdd(1)BUG REPORT
This tool is under development at the ASIM department of the LIP6 laboratory.
We need your feedback to improve documentation and tools.
ASIM /LIP6 October 1, 1997 ADDBDDVAR(3)