Too bad we don't have (AFAIK) a join function (like Python's str.join), we could have written this pretty neat solution:
Ask and ye shall receive.
That will work fine so long as none of the positional parameters in $@ contain an embedded newline, which is probably an unlikely scenario (all the other solutions in this thread are similarly flawed).
Regards,
Alister
Last edited by alister; 03-09-2010 at 12:31 PM..
Reason: Removed erroneous alternative
Hi there,
I am trying to move around 3000 files from one directory to another. The mv command is complaining from too many arguments. I tried to use the xargs command but with no luck. Could some body provide help?
Regards (4 Replies)
I discovered that GNU's xargs has a -P option to allow its processes to run in parallel. Great! Is this a GNU thing, or is it supported by other platforms as well? (4 Replies)
Hi,
I have a requirement to RCP the files from remote server to local server.
Also the RCP has to run in parallel. However using 'xargs' retrives 2 file names during each loop. How do we restrict to only one file name using xargs and loop till remaining files.
I use the below code for... (2 Replies)
hi
Could any one please tell me the option using which we can run multiple commands using xargs
I have list of files, I want to run dos2unix and chmod at one shot on them
I tried google n searched man pages but couldnt really find the solution , please help
right now im doing this
ls... (4 Replies)
Dear all ,
any suggest on xargs to combine from (1.txt and 2.txt) to output.txt ?
thanks a lot.
1.txt
0123 BUM-5M BUM-5M 93490481 63839
0124 BUM-5M BUM-5M 112112 ... (3 Replies)
Using the bash shell I'm trying to either create a command for the command line or a script that will show netstat info for a given process name. Here is an example of what I'm trying to do:$ ps aux |grep catalina |grep -v grep | awk '{print $2}'
5132
$ netstat -nlp |grep 5132
(Not all processes... (11 Replies)
Hello, I need some help with xargs
$ ls
aaa bbb ccc ddd$ ls | xargs -I{} ls -la {}
-rw-rw-r--. 1 xxx xx 0 May 30 20:04 aaa
-rw-rw-r--. 1 xxx xx 0 May 30 20:04 bbb
-rw-rw-r--. 1 xxx xx 0 May 30 20:04 ccc
-rw-rw-r--. 1 xxx xx 0 May 30 20:04 dddit's possible to have output like this with... (3 Replies)
Hi,
can anyone tell me in detail ?
what the following do in detail ?
I am trying to get a largest number in a list
Thanks
Tao
LARGEST=$(echo $* | xargs -n1 | sort -nr | tail -1) (3 Replies)
Discussion started by: ccp
3 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)