my input file contains thousands of lines like below
234A dept of education
9788 dept of commerce
8677 dept of engineering
How do i add a delimeter ':' after FIRST 4 CHARACTERS in a line
234A:dept of education
9788:dept of commerce
8677:dept of engineering (7 Replies)
Hello,
in my script i have this lines of code in a while cycle:
..
let j=i+1
t_prod_$i = `cat myfile.csv | grep world | cut -d ";" -f$j`
let i+=1
...
So if i try an echo $t_prod_$i at the end of the cycle i cannot see
the right value obtained by `cat myfile.csv | grep world |... (5 Replies)
Hi,
I have a variable $ID=40 and I need to build a string like
40 40 40 40 40 40
so repeating ID 'n' times separated by spaces.
Any help?
Thanks
Sarah (2 Replies)
Hi All,
I need to concatenate the values in the array into a variable. Currently the code is :
for (( i=1 ; i <= $minCount ; i++ ))
do
var="${var}""${sample_file}"
done
The output is :
/tmp/1/tmp/2/tmp/3/tmp/4/tmp/5/tmp/6/tmp/7/tmp/8/tmp/9/tmp/10
I need a space between... (1 Reply)
#! /bin/csh
set tt=12345_UMR_BH452_3_2.txt
set rr=`echo $tt | cut -d_ -f1`
set rr1=welcome
set ff=$rr $rr1
echo $ff
why $ff returned only 12345 and not 12345welcome? thanks (2 Replies)
Hi all, I'm trying to build a variable name automatically through a for loop for a script I'm working on, basically I want to build the variables named: $JVM_HOME0 or $JVM_HOME1 so that I can loop through some file copy/deletes and a server restart once completed. With the code below, I get this... (3 Replies)
Hi Team!!
Please can anyone tell me why the following line does not work properly?
str3+=$str2
it seems that str3 variable does not keep its value in order to be concatenated in the next iteration! Thus when i print the result of the line above it returns the str2 value
What i want to do is to... (8 Replies)
Hi,
I was trying to work on a file which had the following data format
1 hi
1 this
1 is
1 john
2 hello
3 test
3 case
the expected output file is the below
1 hi, this, is, john
2 hello
3 test, case
I tried using awk or while read, but I couldnt... (13 Replies)
I have a script which is migrated from AIX to Linux & now while running it is no able to concatenate string values
The string concatenation step under while loop is not displaying desired result
Please find below the piece of code:
while read EXT_FILE ; do
EXT_FILE=$EXT_FILE.ext.sent
echo... (7 Replies)
Discussion started by: PreetArul
7 Replies
LEARN ABOUT SUSE
command-not-found
COMMAND-NOT-FOUND(1) http://en.opensuse.org/Sco COMMAND-NOT-FOUND(1)NAME
command-not-found - A command-not-found handler
SYNOPSIS
command-not-found {binary_name} {repository}
ARGUMENTS
The following arguments are required:
binary_name
The name of binary you are looking for.
repository
The name of repository for search. For most cases, use zypp
DESCRIPTION
command-not-found handler is designed to tell users which package contains a missing command.
The handler is integrated to bash(1) and zsh(1) shells and is not necessary to call it directly. Just type a name of the command in your
favourite shell and you'll get a result.
If you consider c-n-f handler useless, just add unset command_not_found_handle to your profile or remove the command-not-found package.
Handler doesn't call the command-not-found binary directly, it only prints info about it. If you want to invoke it automatically, just add
export COMMAND_NOT_FOUND_AUTO=1 to your bash profile.
EXAMPLE : NORMAL USAGE
For example you want to try blender, because you have heard that is an amazing program. So just type blender in shell:
$ blender
You get the following output:
The program 'blender' can be found in the following package:
* blender [ path: /usr/bin/blender, repository: zypp (openSUSE 11.1-0) ]
Try installing with:
sudo zypper install blender
bash: blender: command not found
SEE ALSO scout(1)AUTHOR
Pavol Rusnak <stick@gk2.sk>
Developer
http://gitorious.org/opensus 08/07/2009 COMMAND-NOT-FOUND(1)