The print command lists the path of the file being found. I want the output as the file name along with the date that particular files were created i.e similar to a ls -l command.
I am using find to list all the files that satisfy the selection criteria and delete them using rm. Can I display... (2 Replies)
Hi,
I want to display only the file names of the ls command with a delimiter of comma.
For example:-
ls /etc/dir/N*
gives the following output
/etc/dir/N1 /etc/dir/N2 /etc/dir/N3
I want the output as N1,N2,N3,-->Here i need the final comma also.
Also, here /etc/dir is being... (4 Replies)
Hello to all,
I am looking for a way to display only the names of function (calls & definition) of a C++ source code.There is already a post related to this, but the script is to find the functions using a specific variable, and the replies are not that convincing since they cannot be used for... (2 Replies)
Sun Solaris Unix Question
Haven't been able to find any solution for this situation. Let's just say the file names listed below exist in a directory. I want the find command to find all files in this directory but at the same time I want to eliminate certain file names or files with certain... (2 Replies)
Hi
When i do ls -ltr <file1> then it shows me the date and time of the file
if - for whatever reason file has future date/time stamp then ls -ltr is not showing the time, it just shows only date part ... even if time is ahead by 2 hr than current time.
suppose a file was copied from INDIA... (3 Replies)
OS: RHEL 5.8
shell: bash 3.2.25
Directory /home/guest/ contains these files:
file a
file b
file c
fileD
fileE
fileF
testFile.txt
I'm trying to find the syntax to run ls -ltr against this list of files that is contained within a text file, testFile.txt.
The file testFile.txt has... (4 Replies)
Data files coming in different names in a file name called process.txt.
1. shipments_yyyymmdd.gz
2 Order_yyyymmdd.gz
3. Invoice_yyyymmdd.gz
4. globalorder_yyyymmdd.gz
The process needs to discard all the below files and only process two of the 4 file names available
... (1 Reply)
All,
I am trying to create a report on the duration of an ETL load from the file arrival to the final dump in to a database for SLA's.
Does anyone have any guidance or ideas on how metadata can be extracted; information of a file: like file name, created timestamp, count of records and load... (1 Reply)
Discussion started by: pradeepp
1 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)