If we remove all """ and indenting for readability we are left with:
Bearing in mind that I never use arrays and cannot verify that code. There is probably a spurious comma, but the main problem is that we are expanding "*.pl" on the function call rather than within the function. Needs quotes until the point when you actually want to expand the "*". Better to quote every text variable as good practice. There is also a space character missing on the function header (which might still work in some shells).
Because "ls -l" gives more than one field and more than one line (with tail -5) the best I can suggest is to put quotes round ${f_det}. I really don't know whether this will end up in the array. ... others will.
Btw. If you have further issues, please post what you typed, what you expected to happen, and what actually happened (including any error messages).
Last edited by methyl; 03-04-2010 at 05:50 PM..
Reason: removed "just noticed", added Btw.
hi all,
need help with putting names in an array, i have a few servers which i look up by doing a 'find . -name "*.pid' and the format of the output is like following :
./servername/myserver.pid
i was wondering how can i iterate through and store each name in one array
my code is... (1 Reply)
Hi
Does anybody know if there is a utility/command in ksh which would allow to copy/insert the contents of one string into certain positions of the other?
for example:
A=" ABCDEF "
B="HHH"
I need to insert contents of string "B" into string "A" from position 3 to 5, so... (3 Replies)
I was wondering if ksh supported arrays. I have a script that may work with several hosts. I'd like a means of knowing how many hosts I'm working with and an easy way to access them (as variables) in a loop. I'm assuming there's some kind of foreach in shell scripting. (1 Reply)
The following command is only intermittently successful, depends on the data I give it:
set -A ImageShifts_sorted `awk '/START_SECTION IMAGE_DEFINITION/ {getline;getline;getline;getline; print $2"-"$3}' temp.ASCII | sort -u`
My Error:
set: -1: unknown option
Finally, If I run that... (3 Replies)
Hi All,
My Requirement is as follows:
1. User will input Source Sytem Code as input.
2. I have source system codes as 11, 34, 56, 99, 45 etc.
OS Version: SunOS 5.8 Generic_117350-62 sun4u sparc SUNW,Sun-Fire-V890
My code is like...
echo 'Source System Code: \c'
read varSSCode... (3 Replies)
Hi Guys,
My code is something like this
set -A A1 1 7 13 19
set -A A2 2 8 14 20
set -A A3 3 9 15 21
echo "Enter a number"
read number
for i in 0 2 3 4
do
if }" ]
then
do something
elif }" ]
then
do something
elif }" ]
then
do something (4 Replies)
RedHat 5
KSH
I am creating an array, and then using case to go through and count for specific words. Then the count gets stored as an expression.
string='ftp rcp rsh telnet ftp ftp'
set -A myarray $string
FTPCOUNT="0"
for command in ${myarray}
do
case $command in
ftp) FTPCOUNT=`expr... (2 Replies)
Hi all,
I have the code as below "
echo "File carried list after 1st loop "${fileStreamAssiagnInit}""
and I have the out put for the above code as below :
Output : File carried list after 1st loop abcInd.csv sdgUS.csv sopSing.csv
Here i want to count the number of elements in... (3 Replies)
I want to extract each and single character from a password string and put it in an array.
I tried this :
set -A password "echo $passwd | awk '{for (i=1; i<=length($1); i++) printf "%s ",substr($1,i,1)}'`
It's working as long that the password string doesn't contains any *
I tried a few... (5 Replies)
Hello,
I have a complicated situational find and replace that I wrote in bash because I didn't know how to do everything in awk. The code works but is very slow, as expected.
To create my modified file, I am looping through an array that was populated earlier and making some replacements at... (6 Replies)
Discussion started by: LMHmedchem
6 Replies
LEARN ABOUT CENTOS
grub-render-label
GRUB-RENDER-LABEL(1) User Commands GRUB-RENDER-LABEL(1)NAME
grub-render-label - generate a .disk_label for Apple Macs.
SYNOPSIS
grub-render-label [OPTION...] [OPTIONS]
DESCRIPTION
Render Apple .disk_label.
-b, --bgcolor=COLOR
use COLOR for background
-c, --color=COLOR
use COLOR for text
-f, --font=FILE
use FILE as font (PF2).
-i, --input=FILE
read text from FILE.
-o, --output=FILE
set output filename. Default is STDOUT
-t, --text=STRING
set the label to render
-v, --verbose
print verbose messages.
-?, --help
give this help list
--usage
give a short usage message
-V, --version
print program version
Mandatory or optional arguments to long options are also mandatory or optional for any corresponding short options.
REPORTING BUGS
Report bugs to <bug-grub@gnu.org>.
SEE ALSO
The full documentation for grub-render-label is maintained as a Texinfo manual. If the info and grub-render-label programs are properly
installed at your site, the command
info grub-render-label
should give you access to the complete manual.
grub-render-label (GRUB) 2.02-2ubuntu8.3 July 2018 GRUB-RENDER-LABEL(1)