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Top Forums UNIX for Dummies Questions & Answers Date command to obtain the last month is not working correctly.. Post 302397897 by methyl on Tuesday 23rd of February 2010 08:52:42 AM
Old 02-23-2010
@ungalnanban

The o/p highlights the fact that his date command does not work if today's day number did not exist in the previous month.
e.g. 31/03/10 is a valid date but 31/02/10 is not. The o/s in use translates 31/02/10 into 03/03/10 ! Because the o/p wanted the previous month number it is wrong.
My circumvention is to fool "date" that is mid-month but I can't test the syntax without having a copy of Redhat.

Can you try it on your test system and post the results.
 

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CAL_FROM_JD(3)								 1							    CAL_FROM_JD(3)

cal_from_jd - Converts from Julian Day Count to a supported calendar

SYNOPSIS
array cal_from_jd (int $jd, int $calendar) DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $jd - Julian day as integer o $calendar - Calendar to convert to RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and the date in string form "month/day/year". EXAMPLES
Example #1 cal_from_jd(3) example <?php $today = unixtojd(mktime(0, 0, 0, 8, 16, 2003)); print_r(cal_from_jd($today, CAL_GREGORIAN)); ?> The above example will output: Array ( [date] => 8/16/2003 [month] => 8 [day] => 16 [year] => 2003 [dow] => 6 [abbrevdayname] => Sat [dayname] => Saturday [abbrevmonth] => Aug [monthname] => August ) SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3). PHP Documentation Group CAL_FROM_JD(3)
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