I have a simple script that I want to run every 30 minutes but only when I execute it. I don't want it to be a crontab job.
so i have for example
date
ls -l
who
sleep 1800
The first time it executes correctly but after the first time it nevers execute back again. It should execute after... (2 Replies)
Anyone have an idea why this if statement does not work correctly?
"test2.sh" 18 lines, 386 characters
#!/usr/bin/sh
WARNING=80
CRITICAL=95
check_it()
{
if ] || ];then
echo "YES ] || ]"
else
echo "NO ] || ]"
fi
}
check_it 80.1
check_it 81.1 (3 Replies)
#!/usr/bin/ksh
Does anyone have a good way to set a variable to last month?
For example, today is 20070810. I would like to use the date command to set a variable to last months %m code, which is 07. If I pluck this months value (08) and user expr to do simple math on it, it returns 7 (not... (5 Replies)
We are using Red Hat linux system.
I am transferring my rman backup files to another server.
Here is the command i am using to transfer the files.
/usr/bin/rsync -avpP --delete /xyz/xyz/ 99.99.999.99::db110bkp
Here is the rsync version.
>rsync --version
rsync version 3.0.6 ... (1 Reply)
hi
#!usr/bin/perl -w
local ($date) = `/sbin/date "+%D %X" ` ;
print $date
when i run this in ksh shell it is giving the below error
sh: /sbin/date: not found
but same code is working and displaying date and time in sh shell.
what could be the reason.
pls help (10 Replies)
Hi,
On any given day, I want to capture the month that has gone by - said otherwise, how do I capture last month?
expr date '+%m' - 1
Above expression is giving error.
Please advise
thanks
---------- Post updated at 09:28 AM ---------- Previous update was at 09:11 AM... (1 Reply)
I have requirment to get last date of previous month and the first date of previous 4th month:
Example:
Current date: 20130320 (yyyymmdd)
Last date of previous month: 20130228 (yyyymmdd)
First date of previous 4th month: 20121101 (yyyymmdd)
In my shell --date, -d, -v switches are not... (3 Replies)
Hi ,
Please help me out to write a shell script to obtain the date of first tueday of every month. I am new to shell scripting.
Appreciate your help Thanks. (7 Replies)
Discussion started by: prongs22
7 Replies
LEARN ABOUT CENTOS
cal
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)