02-21-2010
Need best grep option or alternative
Hello,
I am processing a text file which contains only words with few combination of characters (it is a dictionary file).
example:
havana
have
haven
haven't
havilland
havoc
Is there a way to exclude only 1 to 8 character long words which not include space or special characters : '-`~.. so on?
The way I remember I've used long ago for length filter was grep "^[a-z]$" grep "^[a-z][a-z]$" grep "^[a-z][a-z][a-z]$" and so on.. but there should be some easier option?
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LEARN ABOUT OPENSOLARIS
look
look(1) User Commands look(1)
NAME
look - find words in the system dictionary or lines in a sorted list
SYNOPSIS
/usr/bin/look [-d] [-f] [-tc] string [filename]
DESCRIPTION
The look command consults a sorted filename and prints all lines that begin with string.
If no filename is specified, look uses /usr/share/lib/dict/words with collating sequence -df.
look limits the length of a word to search for to 256 characters.
OPTIONS
-d Dictionary order. Only letters, digits, TAB and SPACE characters are used in comparisons.
-f Fold case. Upper case letters are not distinguished from lower case in comparisons.
-tc Set termination character. All characters to the right of c in string are ignored.
FILES
/usr/share/lib/dict/words spelling list
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWesu |
+-----------------------------+-----------------------------+
SEE ALSO
grep(1), sort(1), attributes(5)
SunOS 5.11 29 Mar 1994 look(1)