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Top Forums Shell Programming and Scripting Need best grep option or alternative Post 302397118 by alekkz on Sunday 21st of February 2010 02:39:18 AM
Old 02-21-2010
Need best grep option or alternative

Hello,
I am processing a text file which contains only words with few combination of characters (it is a dictionary file).
example:
havana
have
haven
haven't
havilland
havoc
Is there a way to exclude only 1 to 8 character long words which not include space or special characters : '-`~.. so on?
The way I remember I've used long ago for length filter was grep "^[a-z]$" grep "^[a-z][a-z]$" grep "^[a-z][a-z][a-z]$" and so on.. but there should be some easier option?
 

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look(1) 							   User Commands							   look(1)

NAME
look - find words in the system dictionary or lines in a sorted list SYNOPSIS
/usr/bin/look [-d] [-f] [-tc] string [filename] DESCRIPTION
The look command consults a sorted filename and prints all lines that begin with string. If no filename is specified, look uses /usr/share/lib/dict/words with collating sequence -df. look limits the length of a word to search for to 256 characters. OPTIONS
-d Dictionary order. Only letters, digits, TAB and SPACE characters are used in comparisons. -f Fold case. Upper case letters are not distinguished from lower case in comparisons. -tc Set termination character. All characters to the right of c in string are ignored. FILES
/usr/share/lib/dict/words spelling list ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWesu | +-----------------------------+-----------------------------+ SEE ALSO
grep(1), sort(1), attributes(5) SunOS 5.11 29 Mar 1994 look(1)
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