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Full Discussion: Perl Getopt::Long question - stopping multiple args
Top Forums Shell Programming and Scripting Perl Getopt::Long question - stopping multiple args Post 302395947 by rethink on Wednesday 17th of February 2010 10:11:18 AM
Old 02-17-2010
Thanks Pludi, Ive been playing around and i wonder if you could help me clarify something. I changed the relevant lines (bolded in red below) to make surname an array (which looks like it creates a reference to the array). but it still seems to print only the one argument ?

Am i missing something here? Will a scalar reference to an array always only return the first object in an array ? apologies if ive done something dumb here

Code:
#!/bin/perl
use strict;
use Getopt::Long;

my $firstname = "";
my $surname = "";
my $help = "";

GetOptions (
                "firstname=s"           => \$firstname,
                "surname=s@"             => \$surname,
                "help!"                 => \$help,

                ) or die "Incorrect usage.\n";

if( $help )
{
        print "Common on, it's really not that hard.\n";
} else {

        print "firstname is set to  - @$firstname\n";
        print "surname is set to  - $surname\n";

}

As you can see its still the same

Code:
# ./name.pl --firstname John --surname smith jones    
firstname is set to  - John
surname is set to  - smith

I tried it using this as well
Code:
"surname=s"             => \@surname

...
...

print "surname is set to  - @surname\n";

with the same output, so maybe its not just an issue with references
 

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