First of all read it in list context. It would be easier to parse it afterwards.
I would suggest you use a perl one liner only . Incorporate this logic in your script or use a sed module. using a shell command would probably make it slower.
So your code would look like
This is exactly what sed does.
Hi All,
I would need to generate Oracle Inster scripts from an excel formatted spreadsheet as follows:
This needs to be stripped as follows:
REC 1, REC 2 etc are the separators of the records ...
I beleive a pearl script can be written for this ... anything useful will be of... (8 Replies)
how to use sed command to find and replace a directory
i have a file.. which contains lot of paths ...
for eg.. file contains..
/usr/kk/rr/12345/1
/usr/kk/rr/12345/2
/usr/kk/rr/12345/3
/usr/kk/rr/12345/4
/usr/kk/rr/12345/5
/usr/kk/rr/12345/6
/usr/kk/rr/12345/7... (1 Reply)
I am trying to use a script to replace the header of each file, whose filename are stored within the array $test, using the sed command within a Perl script as follows:
$count = 0;
while ( $count < $#test )
{
`sed -e 's/BIOGRF 321/BIOGRF 332/g' ${test} > 0`;
`cat 0 >... (2 Replies)
Hello,
Can any perl experts help me convert my sed string to perl. I am unsuccessful with this.
I have to remove this string from html files OAS_AD('Top');
I have come up with this. However the requirement is in perl.
for find in $(find . -type f -name "file1.html") ; do cat $find |... (2 Replies)
Experts,
We used to receive our source files with '~^' as row delimiter. This file contains 2500K records and two of the columns having value in HTML formats within the file.
While running the below commands against the file, we are encountering out of memory, could you please help to... (3 Replies)
so in unix this command works works and shows me a list of directories
find . -name \*.xls -exec dirname {} \; | sort -u | > list.txt
but when i try running a perl script to run this command
my $query = 'find . -name \*.xls -exec dirname {} \; | sort -u | > list.txt';... (2 Replies)
Hi
I know sed and awk has options to give range of line numbers, but
I need to replace pattern in specific lines
Something like
sed -e '1s,14s,26s/pattern/new pattern/' file name
Can somebody help me in this....
I am fine with see/awk/perl
Thank you in advance (9 Replies)
Hi Guys
Am working on a bash script but got stuck, in this line:
32 $configValues = '';
What would be the best command to enter the password between the " Perl or sed ?
Been trying with Perl using this command:
perl -pi -e 's/''/Seattle#1669!/g'... (5 Replies)
Discussion started by: Tox
5 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)