What is "system date format" in the application context? You should always use formatting when parsing/displaying the date.
Use "--help" to get list of the available format patterns. Avoid assumptions that the LANG has some predefined value as it is very error prone.
Hi,
I want to know how to change this string to date format
20061102122042 to 02-11-2006 12:20:42
or 02-Nov-2006 12:20:42
Please let me know at the earliest.Thanks in advance.
Regards,
Preetham R. (3 Replies)
Hi All,
this is my second post, last post reply was very helpful.
I have a data that has date in DD/MM/YYYY (07/11/2008) format i want to replace the backslash by a dot(.) so that my awk script can read it inside the C shell script that i have written.
i want to change 07/11/2008 to... (3 Replies)
Hi Guys,
Can someone help me on how to change the date format using sed or any unix command to give my desired output as shown below.
INPUT FILE:
69372,200,20100122T17:56:02,2
53329,500,20100121T11:50:07,2
48865,100,20100114T16:08:16,2
11719,200,20100108T13:32:20,2
DESIRED... (2 Replies)
Dear Friends,
Need your help once again,
I have a variable ( e.g. ${i}) whoch has date in MM/DD/YYYY (E.g. 12/31/2011) format.
I want to change it to DD/MM/YYYY (e.g. 31/12/2011) format.
Request you to guide me as we are unable to do the same.
Thanks in advance
Anu. (1 Reply)
Hi all,
I have a file that every line starts with the date and time. The format is like YYYYMMDDHHMM and I woulk like to change it to MM/DD/YY<space>HH:MM.
I tried to figure out a way to do it with sed, but I don't know how I could reorganize the digits of the first format. Does anyone have any... (1 Reply)
Hi,
I was looking for a script to change the date from one format to other. A search in the forum gave me the below script as a result.
#! /bin/ksh
format=YYYYMMDD
YEAR=${format%????}
DAY=${format#??????}
MON=${format#$YEAR}
MON=${MON%$DAY}
echo $MON/$DAY/$YEAR
I got it... (2 Replies)
Hi
I wish to change date from one format to another in unix.
eg: INPUT DATE: 2013159 (YEAR & NUMBER OF DAY)
OUTPUT DATE required: 20130608 (YYYYMMDD)
how to do it ?
Thanks in advance. (6 Replies)
need some more help please
i have a large file and
i want to change just the date format
with awk or sed
from this
yyyy-mm-dd
2016-04-15 8.30
2016-04-15 7.30
2016-04-13 7.30
2016-04-11 8.30
2016-04-11 7.30
2016-04-08 8.30
2016-04-08 7.30
2016-04-06... (5 Replies)
Discussion started by: bob123
5 Replies
LEARN ABOUT PHP
date_parse_from_format
DATE_PARSE_FROM_FORMAT(3) 1 DATE_PARSE_FROM_FORMAT(3)date_parse_from_format - Get info about given date formatted according to the specified formatSYNOPSIS
array date_parse_from_format (string $format, string $date)
DESCRIPTION
Returns associative array with detailed info about given date.
PARAMETERS
o $format
- Format accepted by DateTime.createFromFormat(3).
o $date
- String representing the date.
RETURN VALUES
Returns associative array with detailed info about given date.
EXAMPLES
Example #1
date_parse_from_format(3) example
<?php
$date = "6.1.2009 13:00+01:00";
print_r(date_parse_from_format("j.n.Y H:iP", $date));
?>
The above example will output:
Array
(
[year] => 2009
[month] => 1
[day] => 6
[hour] => 13
[minute] => 0
[second] => 0
[fraction] =>
[warning_count] => 0
[warnings] => Array
(
)
[error_count] => 0
[errors] => Array
(
)
[is_localtime] => 1
[zone_type] => 1
[zone] => -60
[is_dst] =>
)
SEE ALSO DateTime.createFromFormat(3), checkdate(3).
PHP Documentation Group DATE_PARSE_FROM_FORMAT(3)