I have a file let us name x which contains as follows
Code:
1 3 4 5 7
6 2 1 6 0
2 4 9 7 1
0 4 5 7 0
6 0 7 0 0
In this above data i want to find max num for 2nd column after finding that it should print its respective row and my output should b displayed as another file.I can have so many columns and rows its for eg i 600 rows and 15 columns
I want my output as like below
Code:
max=4
respective rows=2 4 9 7 1
I think i have explained my question of my knowldge
waiting for ur help frds
Thanks in advance
Last edited by Franklin52; 02-16-2010 at 06:49 AM..
Reason: Please use code tags!
hi,
I am a begginer in unix and i want to know how to open a file and read it and separate the numbers & words and storing it in separate files, Using shell scripting.
Please help me out for this.
Regards
S.Kamakshi (2 Replies)
Hi All,
I want to read one number from the file.
Only one number will be there in the file.
then i have to increment the number in my script and put it back in the same file.
Is it possible?
Can anybody help me?
Thanks,
Vinay (6 Replies)
Hi Guys,
I am new to unix.
Actually i want help in writing an single command where
i can actually read specific line number in file where the line number will be passed to command as parameter.
ex.
1 a
2 b
3 c
4 d
And to my command i pass as 2.
so i should get output as 2 b
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2 something else
3 more stuff
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FILES="*"
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do
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if ; then
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Any inputs are appreciated
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Hi all,
I have a file sample.txt
abc
asd
adf
daf
adw
add
adv
wdf
I want to control the number of lines to read
Like if i give input as ./script_name 2 5
required output
asd
adf
daf (2 Replies)
hello guys,
I'm struggled to get a number from a very long text file.
NAtoms= 33 NActive= 30 NUniq= 23 SFac= 1.00D+00 NAtFMM= 60 NAOKFM=F Big=F
Integral buffers will be 131072 words long.
Raffenetti 2 integral format.
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I am new to ksh scripts. I would like to be able to read a file line by line from a certain line number. I have a specific line number saved in a variable, say $lineNumber. How can I start reading the file from the line number saved in $lineNumber? Thanks! (4 Replies)
Discussion started by: dcowboys13
4 Replies
LEARN ABOUT DEBIAN
cdbtrf
CDBTRF - compute an LU factorization of a real m-by-n band matrixA without using partial pivoting or row interchanges SUBROUTINECDBTRF( M, N, KL, KU, AB, LDAB, INFO )
INTEGER INFO, KL, KU, LDAB, M, N
COMPLEX AB( LDAB, * ) Cdbtrf computes an LU factorization of
a real m-by-n band matrix A without using partial pivoting or rowinterchanges.This is the blocked version of the algorithm, calling Level 3
BLAS.M (input) INTEGER The number of rows of the matrix A. M >=
0. N (input) INTEGER The number of columns of the matrix
A. N >;= 0. KL (input) INTEGER The number of subdiagonals
within the band of A. KL >;= 0. KU (input) INTEGER The num-
ber of superdiagonals within the band of A. KU >;= 0. AB
(input/output) REAL array, dimension (LDAB,N) On entry, the ma-
trix A in band storage, in rows KL+1 to 2*KL+KU+1; rows 1 to KL
of the array need not be set. The j-th column of A is stored in
the j-th column of the array AB as follows: AB(kl+ku+1+i-j,j) =
A(i,j) for max(1,j-ku)<;=i<=min(m,j+kl)
On exit, details of the factorization: U is stored as an upper
triangular band matrix with KL+KU superdiagonals in rows 1 toKL+KU+1, and the multipliers used during the factorization arestored in rows KL+KU+2 to 2*KL+KU+1. See below for further de-tails. LDAB (input) INTEGER The leading dimension of the ar-
ray AB. LDAB >;= 2*KL+KU+1. INFO (output) INTEGER = 0: suc-
cessful exit
< 0: if INFO = -i, the i-th argument had an illegal value
> 0: if INFO = +i, U(i,i) is exactly zero. The factorization has
been completed, but the factor U is exactly singular, and divi-sion by zero will occur if it is used to solve a system of equa-tions. The band storage scheme is illustrated by the following
example, when M = N = 6, KL = 2, KU = 1:
On entry: On exit:
* a12 a23 a34 a45 a56 * u12 u23 u34 u45 u56
a11 a22 a33 a44 a55 a66 u11 u22 u33 u44 u55 u66
a21 a32 a43 a54 a65 * m21 m32 m43 m54 m65 *
a31 a42 a53 a64 * * m31 m42 m53 m64 * *
Array elements marked * are not used by the routine.
02-16-2010
