Sponsored Content
Top Forums Shell Programming and Scripting Subtract days from a variable holding date Post 302393518 by infernalhell on Tuesday 9th of February 2010 03:20:09 AM
Old 02-09-2010
well That form couldnt get my requirement..

any other help
 

9 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

global variable not holding its value?

dear there, this kept me awake last night, the variable ${TO} in the following script doesn't seem to hold its value. I have a file ./filelist, which lists all files of interests. I group them by keywords in the filename, and would like to count total number of lines in each group. ... (7 Replies)
Discussion started by: patiobarbecue
7 Replies

2. Shell Programming and Scripting

[BASH] Holding a variable unto other scripts.

Ex: Script 1 has pID=333. I want to take pID to Script 2 so I can retrive 333. How can I do this? (3 Replies)
Discussion started by: Yakuzan
3 Replies

3. UNIX for Advanced & Expert Users

Subtract days to a date in AIX 5.3

good afternoon, can someone help me, I need to make a script where n subtract days to a date. I am using AIX 5.3. Greetings. (4 Replies)
Discussion started by: systemoper
4 Replies

4. Shell Programming and Scripting

Subtract 2 date columns in .csv file and get output as number of days

Hi, I have one .csv file. I have 2 date columns present in file, column 2 and column 3. I need to calculate how many days exist between 2 dates. I am trying to subtract date column 2 from date column 3. Eg: my file look likes s.no, Start_date,End_Date 1, 7/29/2012,10/27/2012 2,... (9 Replies)
Discussion started by: Dimple
9 Replies

5. Shell Programming and Scripting

Subtract months/days from date

Hi, Can you please let me know code for the below (in korn shell) a) Subtract month(s) from given date b) Subtract day(s) from give date c) Subtract month(s) from given timestamp d) Subtract day(s) from give timestamp (1 Reply)
Discussion started by: tostay2003
1 Replies

6. Solaris

Subtract 2 days from timestamp

Hi, I am running on Solaris 11.3. I have a timestamp in this format date +%Y%m%d%H%M . I found some forums saying to use date --d however that didn't work. Is there a way how I can subtract days from timestamp in that format? Thanks (12 Replies)
Discussion started by: nms
12 Replies

7. Shell Programming and Scripting

Get a given date and subtract it to 5 days ago

Hi all, I have been researching to obtain SSL certification expiry for most of our webistes. For some cases, some hosts where not directly accessible so i finally got a solution working with curl using my proxy. This lists the expiry date which i'm finally looking for. # curl --proxy... (4 Replies)
Discussion started by: nms
4 Replies

8. Shell Programming and Scripting

Subtract a file's modification date with current date

SunOS -s 5.10 Generic_147440-04 sun4u sparc SUNW,SPARC-Enterprise Hi, In a folder, there are files. I have a script which reads the current date and subtract the modification date of each file. How do I achieve this? Regards, Joe (2 Replies)
Discussion started by: roshanbi
2 Replies

9. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
DATETIME.ADD(3) 							 1							   DATETIME.ADD(3)

DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::add (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_add (DateTime $object, DateInterval $interval) Adds the specified DateInterval object to the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.add(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); $date->add(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-01'); date_add($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-11 Example #2 Further DateTime.add(3) examples <?php $date = new DateTime('2000-01-01'); $date->add(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-01'); $date->add(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-01 10:00:30 2007-06-05 04:03:02 Example #3 Beware when adding months <?php $date = new DateTime('2000-12-31'); $interval = new DateInterval('P1M'); $date->add($interval); echo $date->format('Y-m-d') . " "; $date->add($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-01-31 2001-03-03 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.sub(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.ADD(3)
All times are GMT -4. The time now is 03:01 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy