Hi ,
I am relatively new to unix...
Can u pls help me out to find out if the first day of the month is a working day ie from (Monday to Friday)...using Date and If clause in Korn shell..
This is very urgent.
Thanks for ur help... (7 Replies)
i have a directory in which there are executable files and these files are added at runtime. now i need a shell script which will be called at a certain interval. this shell script should find the latest executable file in that directory and start that executable. care should be taken that once the... (6 Replies)
Hi everyone,
Please help:)
I have a list of 1000 different files which comes daily to the directory.Some of
the files are not coming to the directory now.
I need to write a shell script to find the latest date and time of the files they
came to the directory. The files should be unique.... (1 Reply)
Hi All,
I need to find the previous month last day minus one day, using shell script. Can you guys help me to do this.
My Requirment is as below:
Input for me will be 2000909(YYYYMM)
I need the previous months last day minus 1 day timestamp. That is i need 2000908 months last day minus ... (3 Replies)
Hello All,
I need a bash shell script to find out a day from the date.For example we give the date(20100227/YYYYMMDD) then we get the day 'Saturday'.
Thanks in advance,
Satheesh (5 Replies)
I try to find the first day of our calender. So I used this script ...
echo -n "The week of the date 01jan0001 : "
echo -n `date -d 00010101 +%A`
echo
But its shows error
bash-3.1$ sh first_day.shThe week of the date 01jan0001 : date: invalid date `00010101' (3 Replies)
Hi, I need help to convert the filenames of my 9-year daily files (1999-2007) from a julian day to yyyy-mm-dd format. my original files are patterned likes the ones below.
1999001.txt
1999002.txt
1999003.txt
1999004.txt ...
1999365.txt
desired output:
19990101.txt
19990102.txt... (3 Replies)
Hi Experts,
i am using the below code get the date of previous day.
#!/usr/bin/ksh
datestamp=`date '+%Y%m%d'`
yest=$((datestamp -1))
echo $yest
When i execute the code i am getting output as:
20130715
What i am trying here is, based on the date passed i am fetching previus day's... (0 Replies)
I have a below file
FILE.cfg
JAN_01
VAR1=4
VAR2=SUM
VAR3=PRIVATE
JAN_10
VAR1=44
VAR2=GUN
VAR3=NATUR
JAN_20
VAR1=3
VAR2=TQN
VAR3=COMMA
code: (JAN_10 is argument passed from script) (6 Replies)
Discussion started by: Roozo
6 Replies
LEARN ABOUT PHP
wordwrap
WORDWRAP(3) 1 WORDWRAP(3)wordwrap - Wraps a string to a given number of charactersSYNOPSIS
string wordwrap (string $str, [int $width = 75], [string $break = "0], [bool $cut = false])
DESCRIPTION
Wraps a string to a given number of characters using a string break character.
PARAMETERS
o $str
- The input string.
o $width
- The number of characters at which the string will be wrapped.
o $break
- The line is broken using the optional $break parameter.
o $cut
- If the $cut is set to TRUE, the string is always wrapped at or before the specified $width. So if you have a word that is larger
than the given width, it is broken apart. (See second example). When FALSE the function does not split the word even if the $width
is smaller than the word width.
RETURN VALUES
Returns the given string wrapped at the specified length.
EXAMPLES
Example #1
wordwrap(3) example
<?php
$text = "The quick brown fox jumped over the lazy dog.";
$newtext = wordwrap($text, 20, "<br />
");
echo $newtext;
?>
The above example will output:
The quick brown fox<br />
jumped over the lazy<br />
dog.
Example #2
wordwrap(3) example
<?php
$text = "A very long woooooooooooord.";
$newtext = wordwrap($text, 8, "
", true);
echo "$newtext
";
?>
The above example will output:
A very
long
wooooooo
ooooord.
Example #3
wordwrap(3) example
<?php
$text = "A very long woooooooooooooooooord. and something";
$newtext = wordwrap($text, 8, "
", false);
echo "$newtext
";
?>
The above example will output:
A very
long
woooooooooooooooooord.
and
something
SEE ALSO nl2br(3), chunk_split(3).
PHP Documentation Group WORDWRAP(3)