02-04-2010
Assigning number of days in the month to a variable
I am writing a script that requires the number of days in any given month.
In the shell, I can use the command:
cal `date +%m` `date +%Y`| grep -v '[A-Za-z]' | wc -w
to give me the number of days in the month, but when I assign it to a variable:
VAR=`cal `date +%m` `date +%Y`| grep -v '[A-Za-z]' | wc -w`
and run the script I get this error message:
/test.sh: command substitution: line 5: syntax error near unexpected token `|'
./test.sh: command substitution: line 5: `| grep -v '[A-Za-z]' | wc -w'
./test.sh: line 5: +%mdate: command not found
Anyone know how I can fix the syntax so that this gets assigned to the var properly?
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Looking for some help on capturing the number of days in a month to set as a loop counter. Any ideas, please let me know. (3 Replies)
Discussion started by: flounder
3 Replies
2. Shell Programming and Scripting
does any one have any ideas how i would go about calculating the number of days left in the month from a bash script ?. I want to do some operations on a csv file according to the result (8 Replies)
Discussion started by: dunryc
8 Replies
3. UNIX for Dummies Questions & Answers
Hi guys!
I need to count the occurence of a certain pattern.
For example the pattern is PC.
the contents of the file sample.txt:
A PC
asdfgadfjkl
asdfa PC sadfaf
fdsPCasdfg
if i use grep -c PC sample.txt
it will display 3 as the number of occurence
how do i save that number to a... (1 Reply)
Discussion started by: khestoi
1 Replies
4. Shell Programming and Scripting
Hi all. I am scripting in a POSIX shell on HPUX.
I am running a script that needs to determine the number of days in a month.
I found this on the forum and it works great:
X=`cal $(date +%m) $(date +%Y) | grep -v '' | wc -w`
The issue is that I am running the script on the 7th day of... (11 Replies)
Discussion started by: lyoncc
11 Replies
5. Shell Programming and Scripting
Hi,
I have an issue in date processing, the issue is I have a month as an int ( 1 - 12 ), the weekday as int ( 0 - 6 , 0 = Sunday), and the week day in month as int ( 0 - 5, 5 = last ex: first sunday, last monday, third tuesday ... ), now from those three parameters is there a possible way to... (5 Replies)
Discussion started by: modn3
5 Replies
6. Programming
Hi,
I have an issue in date processing, the issue is I have a month as an int ( 1 - 12 ), the weekday as int ( 0 - 6 , 0 = Sunday), and the week day in month as int ( 0 - 5, 5 = last ex: first sunday, last monday, third tuesday ... ), now from those three parameters is there a possible way to... (2 Replies)
Discussion started by: modn3
2 Replies
7. Shell Programming and Scripting
hi all
searched google and here, cant find and am begining to suspect there is no options for this.
shell = born
with either the date or cal command I need to display the number of days in current month. can anyone point me in the right direction? (10 Replies)
Discussion started by: rontopia
10 Replies
8. Shell Programming and Scripting
Hi Guru's,
I am working on a shell script from past a month and unable to get rid of automating while working with dates,here's what i have.
inital_date=11012011
final_date=11302011
expected_output= has to be in below format PFB
11012011
11022011
11032011
*
*
*
11102011
*
*... (9 Replies)
Discussion started by: Gaurav198
9 Replies
9. Shell Programming and Scripting
I have a homework assignment:
----------------------------------------
"Display" the number of days in the current month. For example:
September 1996 has 30 days
----------------------------------------
I am trying to just display the head of cal to start the sentence.
eg. cal | head
... (1 Reply)
Discussion started by: eaafuddy
1 Replies
10. Shell Programming and Scripting
Hello Guys,
I would like to ask you for a favor. Could you please help me how can I assign any number as the parameter to a, from stdin (-c), in the following command line by using the 'switch' in a script?
awk '$8>a {print "File name:" $5,$8}'
I would also appreciate if you can share any... (1 Reply)
Discussion started by: Padavan
1 Replies
LEARN ABOUT PHP
dateinterval.format
DATEINTERVAL.FORMAT(3) 1 DATEINTERVAL.FORMAT(3)
DateInterval::format - Formats the interval
SYNOPSIS
public string DateInterval::format (string $format)
DESCRIPTION
Formats the interval.
PARAMETERS
o $format
-
The following characters are recognized in the $format parameter string. Each format character must be prefixed by a percent sign (
%).
+------------------+--------------------------------------+---+
|$format character | | |
| | | |
| | Description | |
| | | |
| | Example values | |
| | | |
+------------------+--------------------------------------+---+
| | | |
| % | | |
| | | |
| | Literal % | |
| | | |
| | | |
| | % | |
| | | |
| | | |
| Y | | |
| | | |
| | Years, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03 | |
| | | |
| | | |
| y | | |
| | | |
| | Years, numeric | |
| | | |
| | | |
| | 1, 3 | |
| | | |
| | | |
| M | | |
| | | |
| | Months, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 12 | |
| | | |
| | | |
| m | | |
| | | |
| | Months, numeric | |
| | | |
| | | |
| | 1, 3, 12 | |
| | | |
| | | |
| D | | |
| | | |
| | Days, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 31 | |
| | | |
| | | |
| d | | |
| | | |
| | Days, numeric | |
| | | |
| | | |
| | 1, 3, 31 | |
| | | |
| | | |
| a | | |
| | | |
| | Total number of days as a result of | |
| | a DateTime::diff or (unknown) other- | |
| | wise | |
| | | |
| | | |
| | 4, 18, 8123 | |
| | | |
| | | |
| H | | |
| | | |
| | Hours, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 23 | |
| | | |
| | | |
| h | | |
| | | |
| | Hours, numeric | |
| | | |
| | | |
| | 1, 3, 23 | |
| | | |
| | | |
| I | | |
| | | |
| | Minutes, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 59 | |
| | | |
| | | |
| i | | |
| | | |
| | Minutes, numeric | |
| | | |
| | | |
| | 1, 3, 59 | |
| | | |
| | | |
| S | | |
| | | |
| | Seconds, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 57 | |
| | | |
| | | |
| s | | |
| | | |
| | Seconds, numeric | |
| | | |
| | | |
| | 1, 3, 57 | |
| | | |
| | | |
| R | | |
| | | |
| | Sign " -" when negative, " +" when | |
| | positive | |
| | | |
| | | |
| | -, + | |
| | | |
| | | |
| r | | |
| | | |
| | Sign " -" when negative, empty when | |
| | positive | |
| | | |
| | | |
| | -, | |
| | | |
+------------------+--------------------------------------+---+
RETURN VALUES
Returns the formatted interval.
NOTES
Note
The DateInterval::format method does not recalculate carry over points in time strings nor in date segments. This is expected
because it is not possible to overflow values like "32 days" which could be interpreted as anything from "1 month and 4 days" to "1
month and 1 day".
EXAMPLES
Example #1
DateInterval example
<?php
$interval = new DateInterval('P2Y4DT6H8M');
echo $interval->format('%d days');
?>
The above example will output:
4 days
Example #2
DateInterval and carry over points
<?php
$interval = new DateInterval('P32D');
echo $interval->format('%d days');
?>
The above example will output:
32 days
Example #3
DateInterval and DateTime::diff with the %a and %d modifiers
<?php
$january = new DateTime('2010-01-01');
$february = new DateTime('2010-02-01');
$interval = $february->diff($january);
// %a will output the total number of days.
echo $interval->format('%a total days')."
";
// While %d will only output the number of days not already covered by the
// month.
echo $interval->format('%m month, %d days');
?>
The above example will output:
31 total days
1 month, 0 days
SEE ALSO
DateTime::diff.
PHP Documentation Group DATEINTERVAL.FORMAT(3)