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Full Discussion: Text stream K&R exercises
Operating Systems OS X (Apple) Text stream K&R exercises Post 302392206 by Jammer Six on Wednesday 3rd of February 2010 03:48:11 PM
Old 02-03-2010
Okay, here we go.

Life interfered, AGAIN, with my programming.

This is the basic program, now I'm looking at the problems with printing the histogram vertically.

More planning, obviously. Have to know in advance how high the highest bar will be, and how wide the graph will be.

Then I need to figure a way to lock the vertical bars into the correct horizontal column...

Anyway, here's the horizontal version.

I spent some time playing around with labels, but I couldn't get the "%" sign to print! Printf uses it for the signal, and it was really annoying.

Code:
/*
 *  hist.c
 *  
 * Exercise 1-13. Write a program to print a histogram of the lengths of words in its input.
 * This version prints a horizontal histogram. It uses the character █ for the bars.
 * 
 */


#include <stdio.h>
#define	MAX_WORD_LENGTH	30	// The maximum number of letters in a word.
#define	NUMBER_WORDS 0	// To call the first member of the array.

float wordLength	[MAX_WORD_LENGTH]; // array to hold the counts; zero is the number of words

main() {
	
	int c; // counter
	int character; // the character we're looking at
	float p;	// printing counter
	int s;  // printing symbol
	
	for (c = 0; c <= MAX_WORD_LENGTH; c++) {
		wordLength[c] = 0;
	} // end initialization for loop
	
	c = 0; // set count to zero
	
	while ((character = getchar()) != EOF) { // get the character, stuff it into character, check for EOF
		
		
		if ((character >= 'a' && character <= 'z') || // if it's a lower case letter or
			character >= 'A' && character <= 'Z') {   // an upper case letter
			c++; //increment the counter
			
		} // end if
		
		else { // it's the end of the word, c holds the length of the word we just found.
			wordLength[c]++;
			wordLength[NUMBER_WORDS]++; // increment number of words
			c = 0; // re-set the counter for the next word
		} // end else
	} // end while loop
	
	/*******************
	 Printing- we've left the while loop because an EOF showed up
	 *******************/
	
	for (c = 1; c <= MAX_WORD_LENGTH; c++) {
		
		/* Note that this for loop starts with one, not zero.
		 This is because zero holds the number of words,
		 and each word had at least one letter. */
		
		/**************************************
		 This is a test printing sequence I used to make sure the right
		 members of the array were incrementing. I left it here in case
		 final protective fire full panic testing was needed.
		printf("C-");
		printf("%d", c);
		printf(" is ");
		printf("%f \n", wordLength[c]);
		 **************************************/		 
		
		p = ((wordLength[c] / wordLength[NUMBER_WORDS]) * 100); // Each symbol is 1%
		
		printf("%2.0d", c);
		printf(" letters:");

		for (s = 1; s <= p; s++) {
					printf("█");
				} // end printing for loop
		
		printf("\n");
		
	} // end for loop
} // end main



---------- Post updated at 12:48 ---------- Previous update was at 12:44 ----------

Quote:
Originally Posted by pludi
The most important thing I learned in my programming class: it doesn't matter what languages you know, but what algorithms, and whether or not you can apply them when needed. The above algorithm could probably be written in Perl in 2 lines (4, if you insist on strictures and warnings), but the algorithm would still be the same.
Pludi, I've been thinking about this statement since I read it.

I'm starting to see what you mean, but I don't know.

Do you mean that knowing the principle of "For (x = 0, x<=y, x++)" is more important than knowing how to write it?

I think I see that. If you know what you want to do, then you only have to find out how to write it, rather than figuring out how to do it.

Or something. Smilie
 

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