Hi Friends,
I'm doing on script which finds all the files with time stamp and makes them tar and zip, based on their respective month&year. for instance "mar-2004.tar.zip" will contain all the files which was created/accessed/modified on mar-2004. like this the entire filesystem should be taken... (1 Reply)
Hi,
I'm working on a Informix4gl module. I'm just trying to find out any built-in function to fetch only the year/month from an INTERVAL YEAR TO MONTH data value.
Please let me know, if there are any functions to do this. If not, let me know for any alternative solutions to attain this.
... (5 Replies)
Hi
I have files like
abc_cd_20110302_123423
abc_cd_ef_20110301_123423
abc_cd_ef_20110403_123423
abc_ef_20110401_123423
I want to extract the
the year and month associated with each file.
I tried
logfileyearmonth=`echo $logfile | awk -F_'{print $NF}'`
Any other way can I... (6 Replies)
I have created this program to get the next month and year. Is there a simpler way.
#!/bin/ksh
string=`cat Date.txt`
year=`echo $string | cut -c 1-4`
month=`echo $string | cut -c 5-6`
echo $year$month
mon=`expr $month + 1`
if ; then
mon=0$mon
echo $mon
fi
if ; then
month=01
... (2 Replies)
Hi All,
I need to find all files other than first two files dates & last file date for month and month/year wise list.
lets say there are following files in directory
Mar 19 2012 c.txt
Mar 19 2012 cc.txt
Mar 21 2012 d.txt
Mar 22 2012 f.txt
Mar 24 2012 h.txt
Mar 25 2012 w.txt
Feb 12... (2 Replies)
Hi All,
I find all files for same month and year
lets say there are following files in directory
-rwxr-xr-x 1 user userg 1596 Mar 19 2012 c.txt
-rwxr-xr-x 1 user userg 1596 Mar 21 2012 d.txt
-rwxr-xr-x 1 user userg 1596 Mar 22 2012 f.txt
-rwxr-xr-x 1... (8 Replies)
how to find all files other than first two dates & last date per month and year
Hi All,
lets say there are following files in directory
-rwxr-xr-x 1 user userg 1596 Mar 19 2012 a.txt
-rwxr-xr-x 1 user userg 1596 Mar 19 2012 b.txt
-rwxr-xr-x 1 user userg ... (6 Replies)
Hi Folks -
I'm looking for the best way to to increment fiscal weeks - allow me to explain.
At my one client, 10/01/17 was the beginning if year fiscal year 2018.
Each week, I need to manage a unique set of variable that are updated in my application - they are called substitution variables.... (31 Replies)
Discussion started by: SIMMS7400
31 Replies
LEARN ABOUT MOJAVE
datetime::leapsecond
DateTime::LeapSecond(3) User Contributed Perl Documentation DateTime::LeapSecond(3)NAME
DateTime::LeapSecond - leap seconds table and utilities
VERSION
version 1.06
SYNOPSIS
use DateTime;
use DateTime::LeapSecond;
print "Leap seconds between years 1990 and 2000 are ";
print DateTime::Leapsecond::leap_seconds( $utc_rd_2000 ) -
DateTime::Leapsecond::leap_seconds( $utc_rd_1990 );
DESCRIPTION
This module is used to calculate leap seconds for a given Rata Die day. It is used when DateTime.pm cannot compile the XS version of this
code.
This library is known to be accurate for dates until December 2009.
There are no leap seconds before 1972, because that's the year this system was implemented.
o leap_seconds( $rd )
Returns the number of accumulated leap seconds for a given day, in the range 0 .. 22.
o extra_seconds( $rd )
Returns the number of leap seconds for a given day, in the range -2 .. 2.
o day_length( $rd )
Returns the number of seconds for a given day, in the range 86398 .. 86402.
SEE ALSO
<http://hpiers.obspm.fr/eop-pc/earthor/utc/leapsecond.html>
http://datetime.perl.org
AUTHOR
Dave Rolsky <autarch@urth.org>
COPYRIGHT AND LICENSE
This software is Copyright (c) 2013 by Dave Rolsky.
This is free software, licensed under:
The Artistic License 2.0 (GPL Compatible)
perl v5.18.2 2017-10-06 DateTime::LeapSecond(3)