Hi Guys here I am again,
I have two files in a specified location.
Location ex: /opt/xdm/input/
input file names: 1. abc_app.yyyymmdd.dtd
2. abd_app.yyyymmdd.dtd
I need to build a code that reads the files from the location based on the oldest date and cuts the date part... (5 Replies)
Hi,
Is it possible to remove the first part of the file name using find.
i.e i have something like 2006abc.txt , 1007bed.txt etc,
I wanna rename them to abc.txt , bed.txt
I tried some stupid way..
find . -name '*.txt' -exec mv {} `cut -f2-5 -d"_" {}` \;
somehow iam not getting it.
... (3 Replies)
I have an xml file, from where I need to take out Application2 entries and keep the others. I need to remove from <product> to </product> and the key element to look for while removing should be <application> as other pairs can be same for others.
<product>
... (10 Replies)
Hi,
I have two input files as
File1 :
ABC:client1:project1
XYZ:client2-aa:project2
DEF:client4:proj
File2 :
client1:W-170:xx
client2-aa:WT-04:yy
client4:L-005A:zz
Also, array of valid values can be hardcoded like
Output :
ABC:W:project1
XYZ:WT:project2 (1 Reply)
hi all,
how can i use grep or awk to clean the following input data:
n<>the<>96427210 861521305 123257583
n<>obj<>79634223 861521305 79634223
n<>nmod<>68404733 861521305 68422718
where the desired results is to remove all non-numeric characters?:
96427210 861521305 123257583 ... (5 Replies)
Dear all,
How can I remove duplicated column in a text file?
Input:
LG10_PM_map_19_LEnd 1000560 G AA AA AA AA AA GG
LG10_PM_map_19_LEnd 1005621 G GG GG GG AA AA GG
LG10_PM_map_19_LEnd 1011214 A AA AA AA AA GG GG
LG10_PM_map_19_LEnd 1011673 T TT TT TT TT CC CC... (1 Reply)
Gents,
Is there the chance to remove part of the file,
Taking in consideration this condition.
For each record the first row start with the string % VE
should be 56 rows for each records..
first row = % VE
last row = % sw
total 56 rows for each record.
Then in the case that the... (4 Replies)
Discussion started by: jiam912
4 Replies
LEARN ABOUT DEBIAN
zip_replace
ZIP_ADD(3) Library Functions Manual ZIP_ADD(3)NAME
zip_add , - .Nm zip_replace add file to zip archive or replace file in zip archive
LIBRARY
libzip (-lzip)
SYNOPSIS
#include <zip.h>
zip_int64_t zip_add(struct zip *archive, const char *name); "struct zip_source *source"
int zip_replace(struct zip *archive, zip_uint64_t index); "struct zip_source *source"
DESCRIPTION
The function zip_add adds a file to a zip archive, while zip_replace replaces an existing file in a zip archive. The argument archive
specifies the zip archive to which the file should be added. name is the file's name in the zip archive (for zip_add ), while index speci-
fies which file should be replaced (for zip_replace ). The data is obtained from the source argument. See the zip_source_* functions
cited in SEE ALSO.
RETURN VALUES
Upon successful completion, zip_add returns the index of the new file in the archive, and zip_replace returns 0. Otherwise, -1 is returned
and the error code in archive is set to indicate the error.
EXAMPLES
struct zip_source *s;
if ((s=zip_source_buffer(archive, buffer, len)) == NULL ||
zip_add(archive, name, s) 0) {
zip_source_free(s);
printf("error adding file: %s0, zip_strerror(archive)); }
ERRORS
zip_add and zip_replace fail if:
[ZIP_ER_EXISTS]
There is already a file called name in the archive. (Only applies to zip_add ).
[ZIP_ER_INVAL]
source or name are NULL, or index is invalid.
[ZIP_ER_MEMORY]
Required memory could not be allocated.
SEE ALSO libzip(3), zip_source_file(3), zip_source_filep(3), zip_source_function(3), zip_source_zip(3)AUTHORS
Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at>
NiH March 10, 2009 ZIP_ADD(3)