I have a perl script which prints epoch value of date in milliseconds as the output.
My reuirement is that once the output is printed,the day variable shld increment by 1 and when i execute the script for the second time the output shld be for the new day value.
My script looks as below:
======================================================
======================================================
1st execution output will be for "14th of August"
When i execute second time the output shld be for 15th August.
Can someone pls suggest.
Last edited by Franklin52; 01-06-2010 at 04:49 AM..
Reason: Please use code tags!
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Hi,
Iam new to scripting language.:o
can someone help me out solving this thread?hopingly ya....:)
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DATA_DATE=20100107
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The code should work... (3 Replies)
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Today_Dt=`date "+%Y-%m-%d"`
So the Today date is 2010-05-03
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2010-04-27
2010-04-02
2010-04-18
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.. (1 Reply)
hi experts,
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I need to incerement the date variable for instance
echo `date '+%F %H:%M:00'`
this produces
2014-08-02 20:05:00
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Discussion started by: isenhiem
2 Replies
LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3)cal_from_jd - Converts from Julian Day Count to a supported calendarSYNOPSIS
array cal_from_jd (int $jd, int $calendar)
DESCRIPTION cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $jd
- Julian day as integer
o $calendar
- Calendar to convert to
RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and
the date in string form "month/day/year".
EXAMPLES
Example #1
cal_from_jd(3) example
<?php
$today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($today, CAL_GREGORIAN));
?>
The above example will output:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
SEE ALSO cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).
PHP Documentation Group CAL_FROM_JD(3)