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Full Discussion: Date Validation
Top Forums Shell Programming and Scripting Date Validation Post 302384489 by cfajohnson on Tuesday 5th of January 2010 01:09:45 PM
Old 01-05-2010
Quote:
Originally Posted by vkca
the user have to input the date format in mmddmmhhyyyy (month,date,minutes,hour,year)
i want a shell script to check whether the user has properly input in the above said manner.
kindly advice

Code:
read date
if [ ${#date} -lt 12 ]
then
  echo Not enough information
elif [ ${#date} -gt 12 ]
then
  echo Too much information
else
  case $date in
    *[!0-9]*) echo Invalid character entered ;;
    *) echo Thank you ;;
  esac
fi

Then you should check that the values for each component are within a valid range.
 

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DATETIMEIMMUTABLE.FORMAT(3)						 1					       DATETIMEIMMUTABLE.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTimeImmutable.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIMEIMMUTABLE.FORMAT(3)
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