12-29-2009
Variable Substitution
Hi ,
I have a variable as follows,
Temp=`cat ABC.txt | cut -c5-`
This will yeild a part of the date. say , 200912.
I would like to substitute this variable's value in a filename.
eg: File200912F.zip
when i say File$TempF.zip , it is not substituting.
Any help ?
Thanks in advance..
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LEARN ABOUT PHP
ziparchive.open
ZIPARCHIVE.OPEN(3) 1 ZIPARCHIVE.OPEN(3)
ZipArchive::open - Open a ZIP file archive
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mixed ZipArchive::open (string $filename, [int $flags])
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Opens a new zip archive for reading, writing or modifying.
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PHP Documentation Group ZIPARCHIVE.OPEN(3)