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Operating Systems Solaris Bad command error for date conversion Post 302383047 by jyothi_wipro on Monday 28th of December 2009 06:37:41 AM
Old 12-28-2009
Hi All,

For my above query,iam running my script in the below way:
date Mon Dec 28 10:31:33 IST 2009
Date_val=`date "+%m%d%y%H%M%S"`
echo $Date_val

And i get the output as 122809164608
But when i convert 122809164608 back to day month year format it gives me the output for 1973 ie as below
Thu Nov 22 15:08:25 IST 1973

But I want for the date i provide.
Can someone tell where am I goin wrong?

Regards,
Jyothi
jyothi_wipro
 

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CONVDATE(1)						      General Commands Manual						       CONVDATE(1)

NAME
convdate - convert time/date strings and numbers SYNOPSIS
convdate [ -c ] [ -n ] [ -s ] arg... DESCRIPTION
Convdate translate the date/time strings specified as arguments on its command line, outputting the results one to a line. OPTIONS
-c If the ``-c'' flag is used, then each argument is taken to be a time_t and is output in ctime format. -n If the ``-n'' flag is used, then each argument is taken as a date string to be parsed by parsedate(3) and is output as a time_t; see time(2). -s If the ``-s'' flag is used, then each argument is taken as a date string to be parsed by parsedate(3) and is output as a string for- matted by ctime(3). This is the default. EXAMPLES
% convdate 'feb 10 10am' Sun Feb 10 10:00:00 1991 % convdate 12pm 5/4/90 Fri Dec 13 00:00:00 1991 Fri May 4 00:00:00 1990 % convdate -n 'feb 10 10am' '12pm 5/4/90' 666198000 641880000 % convdate -c 666198000 Sun Feb 10 10:00:00 1991 HISTORY
Written by Rich $alz <rsalz@uunet.uu.net>. This is revision 1.2, dated 1998/05/20. SEE ALSO
parsedate(3). CONVDATE(1)
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