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Top Forums Programming How to evaluate which coding approach is best? Post 302380220 by Corona688 on Monday 14th of December 2009 02:37:28 PM
Old 12-14-2009
It's very hard to give a general answer without knowing what methods are being considered.

"Best for what" is often a good question... As an example, hash tables can be very fast to read best-case, but used badly they can be no better than a linear search. They're also space-inefficient, strewing information thinly by design... You wouldn't want to use them to store huge amounts of data. Trees are slower to read than a hash table's best, but a balanced tree's worst case time is smaller than a poorly hashed table -- but adding to or changing a tree can be complicated and slow since it may need balancing. Not all data is really suitable for either anyway...

So, more information's needed.
 

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Tie::SubstrHash(3pm)					 Perl Programmers Reference Guide				      Tie::SubstrHash(3pm)

NAME
Tie::SubstrHash - Fixed-table-size, fixed-key-length hashing SYNOPSIS
require Tie::SubstrHash; tie %myhash, 'Tie::SubstrHash', $key_len, $value_len, $table_size; DESCRIPTION
The Tie::SubstrHash package provides a hash-table-like interface to an array of determinate size, with constant key size and record size. Upon tying a new hash to this package, the developer must specify the size of the keys that will be used, the size of the value fields that the keys will index, and the size of the overall table (in terms of key-value pairs, not size in hard memory). These values will not change for the duration of the tied hash. The newly-allocated hash table may now have data stored and retrieved. Efforts to store more than $table_size elements will result in a fatal error, as will efforts to store a value not exactly $value_len characters in length, or reference through a key not exactly $key_len characters in length. While these constraints may seem excessive, the result is a hash table using much less internal memory than an equivalent freely-allocated hash table. CAVEATS
Because the current implementation uses the table and key sizes for the hashing algorithm, there is no means by which to dynamically change the value of any of the initialization parameters. The hash does not support exists(). perl v5.18.2 2013-11-04 Tie::SubstrHash(3pm)
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