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Full Discussion: Check input date format?
Top Forums Shell Programming and Scripting Check input date format? Post 302380093 by becket on Monday 14th of December 2009 08:01:10 AM
Old 12-14-2009
date.sh
Code:
#!/bin/sh
echo $1 | awk -f date.awk

date.awk
Code:
BEGIN{
FS="."
}
{
 if ( $1 > 0 && $1 <= 31  &&  $2 > 0 && $2 <= 12 && $3 > 0 && length($3) == 4 ) {
 print "DATE FORMAT OK"
 }
 else{
 print "DATE FORMAT NOK"

 }
}

USAGE : date.sh StringDate
 

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LEARN ABOUT PHP

datetimeimmutable.format

DATETIMEIMMUTABLE.FORMAT(3)						 1					       DATETIMEIMMUTABLE.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS

       public string DateTime::format (string  $format)

DESCRIPTION

       string DateTimeImmutable::format (string  $format) string DateTimeInterface::format (string  $format)

       Procedural style
       string date_format (DateTimeInterface  $object, string  $format)

	Returns date formatted according to given format.

PARAMETERS

	      o $object
		-Procedural style only: A DateTime object returned by date_create(3)

	      o $format
		- Format accepted by date(3).

RETURN VALUES

	Returns the formatted date string on success or FALSE on failure.

EXAMPLES

       Example #1

	      DateTimeImmutable.format(3) example

	      Object oriented style

	      <?php
	      $date = new DateTime('2000-01-01');
	      echo $date->format('Y-m-d H:i:s');
	      ?>

	      Procedural style

	      <?php
	      $date = date_create('2000-01-01');
	      echo date_format($date, 'Y-m-d H:i:s');
	      ?>

	      The above example will output:

	      2000-01-01 00:00:00

NOTES

	This method does not use locales. All output is in English.

SEE ALSO 
date(3).
PHP Documentation Group 											       DATETIMEIMMUTABLE.FORMAT(3)
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