Hi all,
This problem has cost me half a day, and i still do not know how to do.
Any help will be appreciated. Thanks advance.
I want to use a variable as the first parameters of gsub function of awk.
Example:
{
...
arri]=gsub(i,tolower(i),$1)
(which should be ambraced by //)
...
} (1 Reply)
Hello,
I have a variable that displays the following results from a JVM....
1602100K->1578435K
I would like to collect the value of 1578435 which is the value after a garbage collection. I've tried the following command but it looks like I can't get the > to work. Any suggestions as... (4 Replies)
Hi all
I want to do a simple substitution in awk but I am getting unexpected output. My function accepts a time and then prints out a validation message if the time is valid. However some times may include a : and i want to strip this out if it exists before i get to the validation. I have shown... (4 Replies)
Hi,
Can some one please explain the following line please throw some light on the ones marked in red
awk '{print $9}' ${FTP_LOG} | awk -v start=${START_DATE} 'BEGIN { FS = "." } { old_line1=$0; gsub(/\-/,""); if ( $3 >= start ) print old_line1 }' | awk -v end=${END_DATE} 'BEGIN { FS="." } {... (3 Replies)
I want to replace comma with space and "*646#" with space.
I am using the following code:
nawk -F"|" '{gsub(","," ",$3); gsub(/\*646\#/"," ",$3);print}' OFS="|" file
I am getting following error:
Help is appreciated (5 Replies)
Hey,
I would like to replace a string by a new one. Teh problem is that both strings should be variables to be flexible, because I am having a lot of files (with the same structure, but in different folders)
for i in daysim_*
do
cd $i/5/
folder=`pwd |awk '{print $1}'`
awk '{ if... (3 Replies)
Hi, I want to print the first column with original value and without any double quotes
The output should look like
<original column>|<column without quotes>
$ cat a.txt
"20121023","19301229712","100397"
"20121023","19361629712","100778"
"20121030A","19361630412","100838"... (3 Replies)
Hello,
I'm trying to substitute a string with leading zero for all the records except the trailer record using awk command and with variables. The input file test_med1.txt has data like below
1234ABC...........................9200............LF... (2 Replies)
Hello, I had some difficulty to understand the gsub function and maybe the regex in this script to remove all the punctuations:
awk 'gsub(//, " ", $0)' text.txtFile text.txt:
This is a test for gsub
I typed this random text file
which contains punctuation like ,.;!'"?/\ etc.
The script... (6 Replies)
Discussion started by: yifangt
6 Replies
LEARN ABOUT MINIX
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for lines containing a given pattern
SYNOPSIS
grep [-elnsv] pattern [file] ...
OPTIONS -e-e pattern is the same as pattern
-c Print a count of lines matched
-i Ignore case
-l Print file names, no lines
-n Print line numbers
-s Status only, no printed output
-v Select lines that do not match
EXAMPLES
grep mouse file # Find lines in file containing mouse
grep [0-9] file # Print lines containing a digit
DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions
accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1
occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a
match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is
returned.
SEE ALSO cgrep(1), fgrep(1), sed(1), awk(9).
GREP(1)