Originally Posted by somu_june

Hi all,

Thanks for your replies. My aim is to get the Time stamp portion from a file using grep and cut command.

My input file inputfile_jobstart_grep contains data like below in a single line

DBsetup DFModify Infilter Uvchange Uvdelete Uvfile Uvread Uvtlconvert Uvwrite cat uvwrite basic block catalog cdict claccount clear.file cname conf.file Job start time=2009-12-05 11:00:00

I want to get Job start time from the input file like 2009-12-05 11:00:00

I tried using below command

echo `cat inputfile_jobstart_grep | \ grep "^[ ]*Jobstart time" | \ cut -f2 -d\=`

but the result is
bash: grep: command not found
bash: cut: command not found

In above command i used caret "^" for matching beging of the line and "*" to match zero or more preceding. As Tene mentioned I'm using back slah "\" to remove special features associated with character like cat and equal sign character in file. But I'm getting below error.