I declared a variable x that gets the count(*) from a table. The table name is also defined as a variable.
What's wrong with this statment :
X=” select count(*) from ${table_name}“
then
y = `${X}${table_name}'
echo ${y}
It throws an error saying count not found.
Please... (1 Reply)
I am just stucked in syntax.This is more like a array and for loop problem.
I want to use ls -l command and get filezise and filename of all filenames in the directory in an array (say array#1).
After 2 minutes of sleep, i want to get the same information in another array (say array#2).
The... (4 Replies)
Dear all,
i m unable to give array decalartion in solaris Operating system shell script
and script was so.sh
declare -a bull
for i in 1 2 3 4 5 6 7 8 9
do
bull=$i
echo "${bull}"
done
it is throwing an error called
so.sh: declare: not found
so.sh: bull=1: not... (20 Replies)
Hello,
I have a problem with the declaration of a function.
This is how I declare the function :
c:63: void foo(threadpool *tp,void (*func)(void*), (void*)arg);
Inside main, I call it like this:
main(){
..........
threadpool y;
c:104: ... (4 Replies)
this is my code
declare -a USERCERT
declare -a CACERT
declare -a KEYSRC
this is the error
+ declare -a USERCERT
./clone.sh: 1: declare: not found
+ declare -a CACERT
./clone.sh: 1: declare: not found
+ declare -a KEYSRC
./clone.sh: 1: declare: not found (11 Replies)
Hi,
Have assigned values in Array and iterating in while loop and would require values outside of the loop. But its returning NULL.
could you please help us how to define Global array declaration in Unix shell scripting?
i am using Kron shell.
Thanks in advance. (2 Replies)