12-01-2009
Thank you both for your replies. Unfortunately I have tried both of them,
1. with the awk script I only ended up getting the headers as the output:
PDB CHAIN StartPos EndPos PDB CHAIN StartPos EndPos
2. With the join command I output to a txt file but I ended up with nothing?
Could you both kindly explain the code to me? Maybe if I get the logic then I can modify it accordingly. Thanks!
---------- Post updated at 04:45 PM ---------- Previous update was at 04:39 PM ----------
I doubled checked, I had wrongly-formatted files so the commands weren't working properly. Both working find now!
Thank you very much!!
PS: Is there a way however to modify it so that I don't end up with duplicates:
For example, I end up with
glelk 1avq A 129 133 1avq A 129 133
which is basically an identical row in both FilesA and FilesB
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PASTE(1) General Commands Manual PASTE(1)
NAME
paste - paste multiple files together
SYNOPSIS
paste [-s] [-d list] file...
OPTIONS
-d Set delimiter used to separate columns to list.
-s Print files sequentially, file k on line k.
EXAMPLES
paste file1 file2 # Print file1 in col 1, file2 in col 2
paste -s f1 f2 # Print f1 on line 1 and f2 on line 2
paste -d : file1 file2
# Print the lines separated by a colon
DESCRIPTION
Paste concatenates corresponding lines of the given input files and writes them to standard output. The lines of the different files are
separated by the delimiters given with the option -s. If no list is given, a tab is substituted for every linefeed, except the last one.
If end-of-file is hit on an input file, subsequent lines are empty. Suppose a set of k files each has one word per line. Then the paste
output will have k columns, with the contents of file j in column j. If the -s flag is given, then the first file is on line 1, the second
file on line 2, etc. In effect, -s turns the output sideways.
If a list of delimiters is given, they are used in turn. The C escape sequences
, , \, and are used for linefeed, tab, backslash,
and the null string, respectively.
PASTE(1)