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Top Forums Shell Programming and Scripting Another IFS post, [ bourne SH only ] ? Post 302375979 by radoulov on Monday 30th of November 2009 09:25:27 AM
Old 11-30-2009
Quote:
what I am saying is I have been told to do it differently in the format of:[...]
Did you ask him why he wants you to do so?

Quote:
I am unsure why exactly I must use OLDIFS, but I assume it's a problem with sh? so far all tests I have done using IFS in while loop in sh, ash, bash, ksh all seem to work fine... So I really have no idea why my tutor seems to think otherwise, would have been helpful if I asked him to expand on this..
There's a potential problem and it's not sh (Bourne Shell) specific. For instance, you may need the previous (most likely the default) value of IFS in case you need to use the shell word splitting latter in your script:

Code:
% cat s
puts(){ 
  printf 'the shell splits my args like this: \n'
  printf '\t\t%s\n' "$@"
  }
  
s=a:b:c ifs=$IFS IFS=: # save the current IFS and change it

puts $s

IFS=$ifs # restore default IFS  

puts $s

Code:
% sh s
the shell splits my args like this: 
                a
                b
                c
the shell splits my args like this: 
                a:b:c

Quote:
I think the basic logic behind it is, 'sh' doesn't handle subshells very well, while bash/ksh etc do handle subshells fine.[...]
Not at all, I meant to use a sub-shell only to avoid affecting the current shell environment:

Code:
% cat s
puts(){ 
  printf 'the shell splits my args like this: \n'
  printf '\t\t%s\n' "$@"
  }

s=a:b:c
  
( 
  IFS=: # inside a sub-shell because of the () 
  echo now inside ...
  puts $s

)

echo now outiside ...

puts $s

Code:
% ash s
now inside ...
the shell splits my args like this: 
                a
                b
                c
now outiside ...
the shell splits my args like this: 
                a:b:c

Quote:
Like I have already mentioned my problems using OLDIFS variable is that my constant variables that i use to echo statements to standard output are missing the n's[...]
I'm not sure if I understand what you're trying to say, but I suppose that you only need to quote your variables while echoing them:

Semi-right:
Code:
echo "$var"

Right:

Code:
printf '%s\n' "$var"

Often wrong:

Code:
echo $var

By post the exact command(s)/output I mean that we need to see:

+ the exact content of the script/code you're executing
+ the exact content of any input/output files (if any)
+ the exact command as issued on the command line and all the output you're getting (if any)
 

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