11-27-2009
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Hello,
How do I make a command line argument required using getopts?
Thanks. (6 Replies)
Discussion started by: yoi2hot4ya
6 Replies
2. Programming
My program usage takes the form for example;
$ theApp 2 "one or more words"
i.e. 3 command line arguments; application name, an integer, some text
My code includes the following 4 lines:
int anInteger;
char words;
sscanf(argv, "%d", &anInteger);
sscanf(argv, "%s", &message);
Based... (2 Replies)
Discussion started by: enuenu
2 Replies
3. UNIX for Dummies Questions & Answers
I am trying to print command line arguments one per second. I have this
while
do
echo "6"
shift
echo "5"
shift
echo "4"
shift
echo "3"
shift
echo "2"
shift
echo "1"
shift
done (2 Replies)
Discussion started by: skooly5
2 Replies
4. UNIX for Dummies Questions & Answers
I have this while loop and at the end I am trying to get it to tell me the last argument I entered. And with it like this all I get is the sentence with no value for $1. Now I tried moving done after the sentence and it printed the value of $1 after every number. I don't want that I just want... (2 Replies)
Discussion started by: skooly5
2 Replies
5. Shell Programming and Scripting
Hi,
I have to store all the command line arguments into an array.
I have the following code.
**********************
#! /bin/sh
set -A arr_no_updates
i=1
while
do
arr_no_updates=$($i)
echo ${arr_no_updates}
i=$(($i+1))
done**************** (1 Reply)
Discussion started by: little_wonder
1 Replies
6. Shell Programming and Scripting
Hi I am executing a KSH script by passing command line arguments
example: Red Green Dark Red Blue
when I am splitting the arguments by using " "(Space) as delimiter
But the colour Dark Red is a single parameter. But it is getting splitted in between
How to avoid this. Please help Also... (4 Replies)
Discussion started by: hemanth424
4 Replies
7. Shell Programming and Scripting
Hi,
i have a perl script named test.pl. It is executed as
cat *.log|test.pl
i need the complete command line args. I tried using basename $0 but im getting test.pl only but not cat *.log...
Can anyone help me on this.
Thanks in advance (3 Replies)
Discussion started by: niteesh_!7
3 Replies
8. Emergency UNIX and Linux Support
Hi,
Can you please hint me how to achieve the below?
Input:
$./script.sh start 1 2
Internally inside the script i want to set a single variable with $2 and $3 value?
Output:
CMD=$1
ARGS=$2 $3
--VInodh (10 Replies)
Discussion started by: vino_hymi
10 Replies
9. Shell Programming and Scripting
Hello All,
I have a Bash Script and an Expect script that together will SSH to another server and
do some stuff there... From within the Bash Script I process the Command Line Arguments,
which are Required Args and Optional Args.
When I call the Expect script from the Bash Script, I pass... (4 Replies)
Discussion started by: mrm5102
4 Replies
10. Shell Programming and Scripting
I'm using getopts to process command line args in a Bash script. The code looks like this:
while getopts ":cfmvhs:t:" option; do
case $option in
c) operationMode="CHECK"
;;
f) operationMode="FAST"
;;
m) ... (6 Replies)
Discussion started by: gencon
6 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)