Hi!,
In my shell scripts, I always create a logfile by adding the following line in the beginning:
exec >file.log 2>&1
This in turn directs all the output to this logfile till the script executes.
But now, I have to write some output to the monitor for the users.
So, i am doing it... (2 Replies)
i want to print the idle time of the users more than 10 days.
for eg:
my "w" command output is like below.
-sh-3.00$ w
03:47:41 up 13 days, 16:59, 3 users, load average: 10.00, 10.00, 10.00
USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT
root :0 - ... (2 Replies)
hi,
I'm trying to create a program that will read a file and then check the file for each letter of the alphabet and then output the letter and the number of times it appears in the file, into a new file... this is what i have so far but it's not working.. if anyone could help that would be nice!... (10 Replies)
Help plz
Does any one have any idea how to compare interval ranges of 2 files.
finding 1-4 (1,2,3,4) of input2 in input1 of same key "a" values (5-10, 30-40, 45-60, 80-90, 100-120 ). Obviously 1-4 is not one of the range with in input1 a. so it should give out of range.
finding 30-33(31,32,33)... (1 Reply)
Hi, I'm fairly new to scripting and Unix. I'm having trouble printing the number of directories and number of files in all the directories in 2 columns using scripts.
#!/bin/bash
echo "# of Directories --------- # of Messages/Files "
numDir= $(find . -type d | wc -l)
numMsg= $(find .... (4 Replies)
Hi Guys,
I am new to python and I am trying to print ouput of Popen on my text screen (tkinter gui).
I was able to make it work on Linux with this code:
Linux: Working
def PrintSomething2():
outputdata = commands.getstatusoutput("sudo fping -f host.list")
for i in outputdata:... (2 Replies)
Hi
I have a file profile.txt with the below input:
{"atgUserId":"736f14c4-eda2-4531-9d40-9de4d6d1fb0f","firstName":"donna","lastName":"biehler","email":"schoolathome42@live.com","receiveEmail":"y
es"},
{"atgUserId":"c3716baf-9bf8-42da-8a44-a13fff68d20f","firstName":"Gilberto... (6 Replies)
So I am writing a bash script that will search a file line by line for unix timestamps, store all of the timestamps into an array, then check how many of those timestamps were created within the last hour, and finally increment a counter every time it finds a timestamp created within the last hour.... (6 Replies)
Hi All,
i am trying to print the df -h ouput in json format. using below script.
#!/usr/bin/env bash
df -h > /tmp/sdf
nawk '{print " "$1" "$2" "$3" "$4" "$5" "$6" "}' /tmp/sdf > /tmp/sdf1
nawk 'NR==1 { for (i=1; i<=NF; i++) { f = i }}{ print $(f), $(f), $(f), $(f), ... (2 Replies)
Discussion started by: sravani25
2 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)