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Full Discussion: grep a specific line from a file
Top Forums Shell Programming and Scripting grep a specific line from a file Post 302374429 by Neo on Tuesday 24th of November 2009 11:58:51 AM
Old 11-24-2009
Have you tried the -m flag?


Quote:
-m NUM, --max-count=NUM
Stop reading a file after NUM matching lines. If the input is standard input from a regular file, and NUM matching lines
are output, grep ensures that the standard input is positioned to just after the last matching line before exiting,
regardless of the presence of trailing context lines. This enables a calling process to resume a search. When grep
stops after NUM matching lines, it outputs any trailing context lines. When the -c or --count option is also used, grep
does not output a count greater than NUM. When the -v or --invert-match option is also used, grep stops after outputting
NUM non-matching lines.
 

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LEARN ABOUT NETBSD

zfgrep

ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME

     zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files

SYNOPSIS

     zgrep [grep-flags] [--] pattern [files ...]

     zegrep [grep-flags] [--] pattern [file ...]

     zfgrep [grep-flags] [--] pattern [file ...]

DESCRIPTION

     zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).

     The grep-flags and pattern arguments are passed on to grep(1).  If an -e flag is found in the grep-flags, zgrep will not look for a pattern
     argument.

     zegrep calls egrep(1), while zfgrep calls fgrep(1).

EXIT STATUS

     In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.

SEE ALSO

     egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)

AUTHORS

     Thomas Klausner <wiz@NetBSD.org>

BSD
								 December 28, 2003							       BSD
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