Hi Gurus
WHat would be the command to check whether there is a file in particular path or not..
for ex: my file name is ExRate_20071501.csv
I can have many files with same pattern but diffrentiated by date..
i have a process where i have to check if files exist in tht folder i have to... (5 Replies)
Hi All,
I need to create a file which contains the list of all the files present in that directory.
e.g.,
ls /export/home/user/*.dat > list_file.dat
but what i am getting is:
$ ls /export/home/user/*.dat > list_file.dat
/export/home/user/*.dat: No such file or directory
But I have... (1 Reply)
I have list of files named file_username_051208_025233.log. Here 051208 is the date and 025233 is the time.I have to run thousands of files daily.I want to put all the files depending on the date of running into a date directory.Suppose if we run files today they should put into 05:Dec:08... (3 Replies)
Hi All,
I would like to do a loop on all the files with extension .out in my directory this files should be sorted alphabetically.
Then I need to assign to each of them a progressive ID of three digits (maybe in HEX format?).
First I tried to list manually the files as
ARRAY=(
A-001.out ... (5 Replies)
Hi,
Please let me know how to find out number of files in a directory excluding existing files..The existing file format will be unknown..each time..
Thanks (3 Replies)
Hi all,
I'm looking over all the internet for finding how to make a count of the files for every directory apart.. not a total result for the xx directories.
For example:
-dir1
file1
file2
-subdir1
-subdir2
file1
-subdir3
file1
-dir2
-dir3
file4
... (9 Replies)
Hi!
I just want to count number of files in a directory, and write to new text file, with number of files and their name
output should look like this,,
assume that below one is a new file created by script
Number of files in directory = 25
1. a.txt
2. abc.txt
3. asd.dat... (20 Replies)
Discussion started by: Akshay Hegde
20 Replies
LEARN ABOUT CENTOS
msguntypot
MSGUNTYPOT(1p) Po4a Tools MSGUNTYPOT(1p)NAME
msguntypot - update PO files when a typo is fixed in POT file
SYNOPSIS
msguntypot -o old_pot -n new_pot pofiles ...
DESCRIPTION
When you fix a trivial error which surely doesn't affect translations (e.g. a typo) in a POT file, you should unfuzzy the corresponding
msgstr in the translated PO files to avoid so extra work to the translators.
This task is difficult and error prone when done manually, and this tool is there to help doing so correctly. You just need to provide the
two versions of the POT file: before the edition and after as marked in the above synopsis, and it all becomes automatic.
HOW TO USE IT
In short, when you discover a typo in one of your [english] message, do the following:
- Regenerate your POT and PO files.
make -C po/ update-po # for message program translations
debconf-updatepo # for debconf translations
po4a po4a.conf # for po4a based documentation translations
or something else, depending on your project's building settings. You know how to make sure your POT an PO files are uptodate, don't
you??
- Make a copy of your POT file.
cp myfile.pot myfile.pot.orig
- Make a copy of all your files.
mkdir po_fridge; cp *.po po_fridge
- Fix your typo.
$EDITOR the_file_in_which_there_is_a_typo
- Regenerate your POT and PO files.
See above.
At this point, the typo fix fuzzied all the translations, and this unfortunate change is the only one between the PO files of your main
directory and the one from the fridge. Here is how to solve this.
- Discard fuzzy translation, restore the ones from the fridge.
cp po_fridge/*.po .
- Manually merge the PO files with the new POT file, but taking the useless fuzzy into account.
msguntypot -o myfile.pot.orig -n myfile.pot *.po
- Cleanups.
rm -rf myfile.pot.orig po_fridge
You're done. The typo was eradicated from msgstr of both your POT and PO files, and the PO files were not fuzzyied in the process. Your
translators love you already.
SEE ALSO
Despite its name, this tool is not part of the gettext tool suite. It is instead part of po4a. More precisely, it's a random Perl script
using the fine po4a modules. For more information about po4a, please see:
po4a(7)AUTHORS
Martin Quinson (mquinson#debian,org)
COPYRIGHT AND LICENSE
Copyright 2005 by SPI, inc.
This program is free software; you may redistribute it and/or modify it under the terms of GPL (see the COPYING file).
Po4a Tools 2014-06-10 MSGUNTYPOT(1p)