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Homework and Emergencies Emergency UNIX and Linux Support Getting last 50 lines after finding a word Post 302371092 by ghostdog74 on Friday 13th of November 2009 10:21:41 AM
Old 11-13-2009
Code:
awk 'BEGIN{tail=50}
{
  a[NR%tail]=$0
}
/pattern/{ for(i=NR+1;i<=NR+tail;i++)print a[i%tail]}
' file

 

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LOOK(1) 						      General Commands Manual							   LOOK(1)

NAME
look - find lines in a sorted list SYNOPSIS
look [ -dfnixtc ] [ string ] [ file ] DESCRIPTION
Look consults a sorted file and prints all lines that begin with string. It uses binary search. The following options are recognized. Options dfnt affect comparisons as in sort(1). -i Interactive. There is no string argument; instead look takes lines from the standard input as strings to be looked up. -x Exact. Print only lines of the file whose key matches string exactly. -d `Directory' order: only letters, digits, tabs and blanks participate in comparisons. -f Fold. Upper case letters compare equal to lower case. -n Numeric comparison with initial string of digits, optional minus sign, and optional decimal point. -t[c] Character c terminates the sort key in the file. By default, tab terminates the key. If c is missing the entire line comprises the key. If no file is specified, /lib/words is assumed, with collating sequence df. FILES
/lib/words SOURCE
/src/cmd/look.c SEE ALSO
sort(1), grep(1) DIAGNOSTICS
The exit status is ``not found'' if no match is found, and ``no dictionary'' if file or the default dictionary cannot be opened. LOOK(1)
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